The supremum of an increasing sequence of plurisubharmonic functions need not be upper semicontinuous, and it may differ from its upper semicontinuous regularization on an exceptional set. For instance, on the unit ball of $\mathbb C^ n$ the functions $\max \{ j^{-1}\log |z_1|,-1\} $ are plurisubharmonic (proposition 5.10.3, proposition 5.9.5) and increase with $j$, since $\log |z_1|<0$ there; their supremum equals $0$ where $z_1\ne 0$ and $-1$ on the hyperplane $\{ z_1=0\} $, while its upper semicontinuous regularization is $0$. We show that the products are nevertheless continuous along increasing sequences. The proof follows the pattern of the decreasing case: the inequality $u_{0,j}\le u_0$ bounds weak limits from above, while the quasi-continuity of the fixed weights, through lemma 7.5.7, supplies the lower bound for the masses. As a consequence, the exceptional set of an upper envelope has outer capacity zero.
Proof.
We first note that $u_{l,j}\le u_ l$ everywhere. Indeed, $u_{l,j}\le u_ l$ almost everywhere, so the plurisubharmonic functions $\max \{ u_{l,j},u_ l\} $ and $u_ l$ agree almost everywhere, and hence everywhere, by the uniqueness of plurisubharmonic representatives in theorem 5.9.1, applied on each connected component of $D$. Consequently $u_{l,1}\le u_{l,j}\le u_ l$, and the sequences are uniformly bounded on each compact subset of $D$.
As in the proof of theorem 7.3.7, we prove the weighted assertion by induction on $q$, for all bounded open sets $D$ and all sequences as in the statement; convergence in capacity is proved at the end. For $q=0$ it follows from dominated convergence with respect to Lebesgue measure. Let $q\ge 1$ and assume the weighted assertion for $q-1$ factors; applying $\mathrm{dd}^{\mathrm{c}}$ to it, with the weight $u_{1,j}$, gives the unweighted assertion for $q$ factors. Put $S_ j=\mathrm{dd}^{\mathrm{c}}u_{1,j}\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_{q,j}$ and $S=\mathrm{dd}^{\mathrm{c}}u_1\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_ q$, so that $S_ j\to S$ weakly.
Weak convergence is a local property (lemma 7.3.6). Fix $x\in D$ and $r>0$ with $\overline{B(x,4r)}\subset D$, and put $B=B(x,3r)$ and $B_1=B(x,4r)$; we prove the convergence on $B(x,2r)$. Subtracting constants does not affect the assertions, since the unweighted assertion for $q$ factors is known, so we may assume that $-N\le u_{l,j},u_ l\le -1$ on $B_1$ for all $l$ and $j$, where $N\ge 1$. Put $\psi =|z-x|^2-9r^2$, choose $\delta _0>0$ such that $\overline{B(x,2r)}\subset \{ \psi <-\delta _0\} $, and replace each function $v$ among the $u_{l,j}$ and $u_ l$ by the function $\max \{ v,A\psi \} $ of (7.3.2), with $U=B_1$, $\delta _0$ in place of $\delta $ and $A=N/\delta _0$. The new functions are plurisubharmonic on $B_1$ and take values in $[-N,0)$ on $B$; the new sequences still increase, satisfy $u_{l,j}\le u_ l$ and converge almost everywhere. The functions do not change on $B(x,2r)$, and by locality neither do the products. On the collar $V=\{ z\in B_1:\psi (z)>-1/A\} $ of $\partial B$ the new functions coincide with $A\psi $.
By locality, on $V$ all the currents considered below coincide with fixed currents, independent of $j$ and $k$. Hence, if $\chi \in C^\infty _ c(B)$ equals $1$ on $B\setminus V$, the integral over $B$ of each of these currents splits into its integral against $\chi $, to which weak convergence applies, and its integral against $(1-\chi )\mathbf1_ B$, which only involves values on $V$ and therefore does not change; we use this without further comment. The currents $-u_{0,j}S_ j$ are positive on $B$, and their masses on compact subsets of $B$ are bounded uniformly in $j$ by theorem 7.2.5; by the compactness part of theorem 5.3.7, every subsequence of $(u_{0,j}S_ j)$ has a further subsequence converging weakly on $B$. Let $\Theta $ be the limit of such a subsequence.
Since $u_{0,j}\le u_0$, the currents $(u_0-u_{0,j})S_ j$ are positive. Let $\varphi $ be a strongly positive test form on $B$ of complementary bidegree. The positive measures $-u_0S_ j\wedge \varphi $ have bounded masses on compact sets, so by theorem 2.6.5 a further subsequence of $u_0S_ j\wedge \varphi $ converges weakly to some $\nu $, and lemma 7.3.4, applied to the constant sequence $f_ j=u_0$ and the measures $S_ j\wedge \varphi \to S\wedge \varphi $, gives $\nu \le u_0S\wedge \varphi $. The measures $(u_0-u_{0,j})S_ j\wedge \varphi $ are positive and converge along this subsequence to $\nu -\Theta \wedge \varphi $, which is therefore positive. Hence $\Theta \wedge \varphi \le u_0S\wedge \varphi $. Evaluating this inequality of measures on a nonnegative test function equal to $1$ on $\operatorname{Supp}\varphi $, we get $(u_0S-\Theta )(\varphi )\ge 0$. Thus $u_0S-\Theta $ is a positive current on $B$, and it vanishes on $V$, since all the currents $u_{0,j}S_ j$ and $u_0S$ coincide there with $A\psi (A\mathrm{dd}^{\mathrm{c}}\psi )^ q$. Write $\gamma =\beta ^{n-q}$.
For fixed $k$ and all $j\ge k$, positivity of $S_ j\wedge \gamma $ and $u_{0,j}\ge u_{0,k}$ give
\[ \int _ Bu_{0,j}S_ j\wedge \gamma \ge \int _ Bu_{0,k}S_ j\wedge \gamma . \]
Let $j\to \infty $ along the subsequence defining $\Theta $. The left-hand side tends to $\int _ B\Theta \wedge \gamma $. The fixed weight $u_{0,k}$ is quasi-continuous for $\operatorname {Cap}_ B$ by theorem 7.5.2, and the functions $u_{l,j}$, $u_ l$ form a family which is uniformly bounded on $B$; so by lemma 7.5.7(2) the right-hand side tends to $\int _ Bu_{0,k}S\wedge \gamma $. By the second assertion of corollary 7.3.8, applied with $a=u_{0,k}$, $b=u_1$ and $R=\mathrm{dd}^{\mathrm{c}}u_2\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_ q\wedge \gamma $, and by symmetry,
\[ \int _ Bu_{0,k}S\wedge \gamma =\int _ Bu_1\, \mathrm{dd}^{\mathrm{c}}u_{0,k}\wedge \mathrm{dd}^{\mathrm{c}}u_2\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_ q\wedge \gamma . \]
As $k\to \infty $, the unweighted assertion for $q$ factors, already established, gives $\mathrm{dd}^{\mathrm{c}}u_{0,k}\wedge \mathrm{dd}^{\mathrm{c}}u_2\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_ q\to \mathrm{dd}^{\mathrm{c}}u_0\wedge \mathrm{dd}^{\mathrm{c}}u_2\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_ q$ weakly, and lemma 7.5.7, with the fixed quasi-continuous weight $u_1$, passes the integral to the limit. A second application of corollary 7.3.8 identifies the limit with $\int _ Bu_0\, \mathrm{dd}^{\mathrm{c}}u_1\wedge \cdots \wedge \mathrm{dd}^{\mathrm{c}}u_ q\wedge \gamma =\int _ Bu_0S\wedge \gamma $. We have shown that $\int _ B\Theta \wedge \gamma \ge \int _ Bu_0S\wedge \gamma $.
Since $u_0S-\Theta $ is positive with compact support in $B$, its trace measure has total mass $\int _ B(u_0S-\Theta )\wedge \gamma \le 0$ and therefore vanishes, and $\Theta =u_0S$ by theorem 5.3.7. Thus every subsequence of $(u_{0,j}S_ j)$ has a further subsequence converging weakly to $u_0S$ on $B$. Hence the whole sequence converges to $u_0S$ on $B$: otherwise there would be a test form $\varphi $ on $B$ and a subsequence along which $|(u_{0,j}S_ j-u_0S)(\varphi )|$ stays bounded away from zero, and no further subsequence of it could converge to $u_0S$. Since the modifications change neither the functions nor the weighted products on $B(x,2r)$, the original weighted products converge on $B(x,2r)$; this completes the induction.
Now that both assertions are known for every $q\le n$, we prove convergence in capacity. Fix $l$, a compact set $K\subset D$ and $\delta >0$. Since $u_{l,j}\le u_ l$, the sets $\{ u_{l,j}>u_ l+\delta \} $ are empty. Covering $K$ by finitely many balls and using subadditivity of outer capacity, we may assume that $K\subset \overline{B(x,r)}$ with $\overline{B(x,4r)}\subset D$; put $L=\overline{B(x,3r/2)}$. Let $\hat u_{l,j}$ and $\hat u_ l$ be the functions obtained by the modification above, on $B=B(x,3r)$; on $\{ \psi <-\delta _0\} \supset L$ we have $\hat u_ l-\hat u_{l,j}=u_ l-u_{l,j}$. These functions are bounded and plurisubharmonic on $B_1$, they satisfy $\hat u_{l,j}\le \hat u_ l$, and both coincide with $A\psi $ on the collar $V$ of $\partial B$. By (7.4.6), applied with $u=\hat u_{l,j}$ and $h=\hat u_ l$,
\[ \operatorname {Cap}_ D\bigl (B\cap \{ \hat u_ l-\hat u_{l,j}>\delta /2\} \bigr )\le \frac{(n+1)!\, 2^{n+1}}{\delta ^{n+1}}\int _ B(\hat u_ l-\hat u_{l,j})(\mathrm{dd}^{\mathrm{c}}\hat u_{l,j})^ n. \]
The right-hand side tends to zero: $\int _ B\hat u_ l(\mathrm{dd}^{\mathrm{c}}\hat u_{l,j})^ n\to \int _ B\hat u_ l(\mathrm{dd}^{\mathrm{c}}\hat u_ l)^ n$ by the unweighted assertion and lemma 7.5.7(2) with the fixed quasi-continuous weight $\hat u_ l$, and $\int _ B\hat u_{l,j}(\mathrm{dd}^{\mathrm{c}}\hat u_{l,j})^ n\to \int _ B\hat u_ l(\mathrm{dd}^{\mathrm{c}}\hat u_ l)^ n$ by the weighted assertion with all factors and the weight equal to $\hat u_{l,j}$; as before, the integrals over $B$ are split by a cutoff. The real function $u_ l-u_{l,j}$ is quasi-continuous on $D$ (theorem 7.5.2 and the remark following definition 7.5.1), so lemma 7.5.4 gives
\[ \begin{aligned} \operatorname {Cap}^*_ D\bigl (K\cap \{ u_ l-u_{l,j}>\delta \} \bigr )& \le \operatorname {Cap}_ D\bigl (L\cap \{ u_ l-u_{l,j}>\delta /2\} \bigr )\\ & \le \operatorname {Cap}_ D\bigl (B\cap \{ \hat u_ l-\hat u_{l,j}>\delta /2\} \bigr )\longrightarrow 0. \end{aligned} \]
$\square$
Proof.
By theorem 5.10.2, $u=F^*$ is plurisubharmonic, and there is a countable subfamily $\{ w_1,w_2,\ldots \} \subset \mathcal F$ with $(\sup _ kw_ k)^*=u$. The functions $v_ j=\max \{ w_1,\ldots ,w_ j\} $ are plurisubharmonic (proposition 5.9.5) and increase to $G=\sup _ kw_ k$, and $G=G^*=u$ almost everywhere by theorem 5.10.2, applied to the countable family. Fix an integer $m\ge 1$. The functions $\max \{ v_ j,-m\} $ are locally bounded and plurisubharmonic on $D$, and they increase almost everywhere to the locally bounded plurisubharmonic function $\max \{ u,-m\} $, so by theorem 7.6.1 they converge to it locally in capacity. For rational $\delta >0$, the set where $\sup _ j\max \{ v_ j,-m\} <\max \{ u,-m\} -\delta $ is contained in $\{ \max \{ v_ k,-m\} <\max \{ u,-m\} -\delta \} $ for every $k$, and the outer capacities of the intersections of the latter sets with a compact set tend to zero as $k\to \infty $. Taking the union over rational $\delta $, countable subadditivity shows that the set
\[ E_ m=\Bigl \{ \sup _ j\max \{ v_ j,-m\} <\max \{ u,-m\} \Bigr \} \]
meets every compact set in a set of outer capacity zero.
If $\sup _ jv_ j(x)<u(x)$, then $u(x)>-\infty $, so $u(x)>-m$ for some integer $m$, and then $x\in E_ m$. Hence $\{ \sup _ jv_ j<u\} \subset \bigcup _ mE_ m$ also meets every compact set in a set of outer capacity zero. Finally, $\sup _ jv_ j\le F\le u$, so $\{ F<F^*\} \subset \{ \sup _ jv_ j<u\} $. (Since outer capacity is defined for all sets, we need not know whether $\{ F<F^*\} $ is Borel.)
$\square$
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