Pome

Proposition 8.7.8103D0E7E46B0

Proposition 8.7.8.103D0E7E46B0 If continuous admissible $u,v$ satisfy

\[ \mathbf1_{\{ u<v\} }H_ m(u)\leq c\mathbf1_{\{ u<v\} }H_ m(v),\qquad 0\leq c<1, \]

then $u\geq v$.

Proof. Choose $b>1$ so that $(1-b^{-1})^ m>c$, and put $p=P(bu-(b-1)v)$ and $z=b^{-1}p+(1-b^{-1})v\leq u$. On $C=\{ p=bu-(b-1)v\} $ the contact comparison gives

\[ \mathbf1_ C\bigl (b^{-m}H_ m(p)+(1-b^{-1})^ mH_ m(v)\bigr ) \leq \mathbf1_ C H_ m(u). \]

Restricting to $\{ u<v\} $ and using the hypothesis shows that $H_ m(p)$ vanishes on $C\cap \{ u<v\} $. Its support lies in $C$, where $p<v$ is equivalent to $u<v$. Thus $H_ m(p)$ vanishes on $\{ p<v\} $. The preceding domination proposition gives $p\geq v$. Since $p\leq bu-(b-1)v$, it follows that $u\geq v$. $\square$

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