Pome

Theorem 21.13.398F3CCCDB83EC

Theorem 21.13.39.8F3CCCDB83EC Let $\varphi \in \mathrm{PSH}_{\mathrm{tor}}(X,\theta )_{>0}$. Then

3FD1A27C837D 21.13.40
\begin{equation} \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi )\Bigr )=\Delta _{Y_{\bullet }}(\theta ,\varphi ). \end{equation}

In particular,

04CC3F6E758B 21.13.41
\begin{equation} n!\operatorname{vol}\Delta (\theta ,\varphi )=\operatorname{vol}\theta _{\varphi }. \end{equation}

Proof. We first reduce to the case where $D|_{U_{\sigma }}=0$. In fact, changing $D$ to $D+\operatorname{div}\chi ^{m_{\sigma }}$ would result in changing $F_{\theta }$ to $F_{\theta }-m_{\sigma }$. Hence, $F_{\varphi }$ changes to $F_{\varphi }-m_{\sigma }$. Therefore, $\Delta (\theta ,\varphi )$ becomes $\Delta (\theta ,\varphi )-m_{\sigma }$. Taking (21.13.6) into consideration, we may assume that $m_{\sigma }=0$.

Step 1. We first reduce to the case where $\theta _{\varphi }$ is a Kähler current.

By 13.13.47, we can find $\psi \in \mathrm{PSH}(X,\theta )$ such that $\psi \leq \varphi $ and $\theta _{\psi }$ is a Kähler current. Taking the average along $T_ c$, we may assume that $\psi $ is $T_ c$-invariant.

For each $t\in (0,1)$, we let

\[ \varphi _ t=(1-t)\psi +t\varphi . \]

Suppose that Kähler current case is known. Then we get

\[ \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi _ t)\Bigr )=\Delta _{Y_{\bullet }}(\theta ,\varphi _ t) \]

for any $t\in (0,1)$. It follows from theorem 21.11.56 that

\[ \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi )\Bigr )\supseteq \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi _ t)\Bigr )= \Delta _{Y_{\bullet }}(\theta ,\varphi _ t) \]

for any $t\in (0,1)$. Thanks to theorem 19.4.30, we have

\[ \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi )\Bigr )\supseteq \Delta _{Y_{\bullet }}(\theta ,\varphi ). \]

Comparing the volumes of both sides using proposition 21.13.28, (19.4.20), and the $\mathcal{I}$-goodness of toric singularities example 18.1.56, we find that

\[ n!\operatorname{vol}\Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi )\Bigr )=\int _ X \theta _{\varphi }^ n=\operatorname{vol}\theta _{\varphi }=n!\operatorname{vol}\Delta _{Y_{\bullet }}(\theta ,\varphi ). \]

In particular, we conclude (21.13.40).

Step 2. We handle the case where $\theta _{\varphi }$ is a Kähler current.

Let $(\varphi _ j)_ j$ be the quasi-equisingular approximation given by 21.13.38.

Now assume that the result is known for each $\varphi _ j$. Then

\[ \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi _ j)\Bigr )=\Delta _{Y_{\bullet }}(\theta ,\varphi _ j). \]

In particular, thanks to proposition 19.4.28,

\[ \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi )\Bigr )\subseteq \Delta _{Y_{\bullet }}(\theta ,\varphi _ j) \]

for each $j\geq 1$. It follows from theorem 19.4.30 that

\[ \Phi _{\mathbb {R}}\Bigl ( \Delta (\theta ,\varphi )\Bigr )\subseteq \Delta _{Y_{\bullet }}(\theta ,\varphi ). \]

Comparing the volumes of both sides using proposition 21.13.28, (19.4.20), and example 18.1.56, we conclude (21.13.40).

Step 3. It remains to prove the assertion for the analytic approximants appearing in Step 2.

By 21.13.38, these approximants may be chosen in the form

\[ \varphi =\frac{1}{q}\log \sum _{i=1}^ a |s_ i|_{h^ q}^2+\mathcal O(1), \]

where $q\in \mathbb Z_{>0}$ and $s_1,\ldots ,s_ a\in \mathrm{H}^0(X,L^ q)$ are toric eigen-sections.

Let $m_1,\ldots ,m_ a\in qP_ D\cap M$ be the lattice points corresponding to $s_1,\ldots ,s_ a$.

Observe that

\[ \begin{aligned} \Delta (\theta ,\varphi ) =& \overline{\nabla F_{\varphi }(N_{\mathbb {R}})}\\ =& \left\{ m\in M_{\mathbb {R}} : F_{\varphi }(n)-\langle m,n \rangle \textup{ is bounded from below} \right\} \\ =& \left\{ m\in M_{\mathbb {R}}: q^{-1}\log \sum _{i=1}^ a \mathrm{e}^{\langle m_ i,n\rangle }-\langle m,n\rangle \textup{ is bounded below in } n \right\} \\ =& q^{-1}\mathrm{Conv}\{ m_1,\ldots ,m_ a\} , \end{aligned} \]

where we have applied (21.13.23) on the second line and 21.11.62 on the third line. Since $m_1,\ldots ,m_ a\in qP_ D$, the preceding formula also shows that

\[ \Delta (\theta ,\varphi )\subseteq P_ D. \]

Thus, if $m\in k\Delta (\theta ,\varphi )\cap M$, then $m\in kP_ D\cap M$, and $\chi ^ m$ indeed determines a global section of $L^ k$.

In particular, by the same separation argument as in 21.11.60, for any $k\in \mathbb {Z}_{>0}$ and any $m\in k\Delta (\theta ,\varphi )\cap M$, we have

\[ |\chi ^ m|^2 \mathrm{e}^{-k\varphi } \]

is bounded from above on $T(\mathbb {C})$. In other words, the section $s$ of $L^ k$ corresponding to $m$ satisfies

\[ s\in \mathrm{H}^0\left(X,L^ k\otimes \mathcal{I}_{\infty }(k\varphi )\right). \]

Therefore,

\[ \nu _{Y_{\bullet }}(s)=\Phi (m)\in k\Delta _ k(\theta ,\varphi ), \]

where $\Delta _ k$ is defined in section 19.4. Hence,

\[ \Phi \Bigl (k\Delta (\theta ,\varphi )\cap M\Bigr )\subseteq k\Delta _ k(\theta ,\varphi ). \]

Letting $k\to \infty $ and applying theorem 19.4.41, we find that

\[ \Phi _{\mathbb {R}}\Bigl (\Delta (\theta ,\varphi )\Bigr ) \subseteq \Delta _{Y_{\bullet }}(\theta ,\varphi ). \]

Comparing the volumes of both sides using proposition 21.13.28 and (19.4.20), we conclude that the equality holds and (21.13.40) follows. $\square$

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