Pome

Proposition 22.1.2987CB041BFCA3

Proposition 22.1.29.87CB041BFCA3 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$ and $C,C'\in \mathbb {R}$. Then

  1. 80F4957A059F

    $(\Gamma +\Gamma ')+C=\Gamma +(\Gamma '+C)=(\Gamma +C)+\Gamma '$;

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    $\Gamma +(C+C')=(\Gamma +C)+C'$.

Proof. This is a direct consequence of proposition 17.15.11. $\square$

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