Proposition 22.1.29.87CB041BFCA3 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$ and $C,C'\in \mathbb {R}$. Then
80F4957A059F$(\Gamma +\Gamma ')+C=\Gamma +(\Gamma '+C)=(\Gamma +C)+\Gamma '$;
036FE960D3D0$\Gamma +(C+C')=(\Gamma +C)+C'$.
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