Remark 22.1.88.9911A537C86C Note that $\tau \mapsto A_{\tau }$ is upper semicontinuous, but not necessarily concave. Let $(A'_{\tau })_{\tau \in \mathbb {R}}$ be the upper concave envelope of $\tau \mapsto A_{\tau }$. Then it can be inductively constructed as follows:
D954EE804570For $\tau \in (\tau _0,\infty )$, we let $A'_{\tau }\equiv -\infty $;
34859AD723A6we set $A'_{\tau _0}=A_{\tau _0}$;
FCE6B95F3C1Fdefine inductively for $j=0,\ldots ,N-1$ the following: For $\tau \in [\tau _{j+1},\tau _ j)$, we set
\[ A'_{\tau }=\max _{i=j+1,\ldots ,N}\left( \frac{\tau _ j-\tau }{\tau _ j-\tau _ i}A_{\tau _ i}+\frac{\tau -\tau _ i}{\tau _ j-\tau _ i}A'_{\tau _ j} \right)\lor A'_{\tau _ j}; \]E47ACD33228Bfor $\tau \in (-\infty ,\tau _ N)$, we set $A'_{\tau }=A_{\tau _ N}$.
This construction is just a reformulation of the general formula proposition 21.11.12.
In particular, $A'_{\tau }\in \mathrm{PSH}(X,\theta )$ for all $\tau \leq \tau _0$.
Note that $A'$ is not necessarily piecewise linear.
Comments
Corrections, questions, and mathematical discussion are welcome. Sign in with GitHub to comment. Comments are public.