Corollary 22.1.100.9D2A9B228E44 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. Then $\Gamma ^{\mathrm{An}}$ defined in definition 22.1.82 admits a unique extension to $\mathrm{PSH}(L^{\mathrm{An}})$.
Corollary 22.1.1009D2A9B228E44
Proof. Observe that the extension is unique if it exists by theorem 22.1.72. We may assume that $\Gamma _{\max }=0$ without loss of generality.
When $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$, our assertion follows from proposition 22.1.98 and proposition 22.1.84.
In general, fix an ample line bundle $H$ on $X$ and a Kähler form $\omega \in c_1(H)$. Then we know that
\[ \Gamma ^{\mathrm{An}}=\left(\Gamma ^{m^{-1}\omega }\right)^{\mathrm{An}}\in \mathrm{PSH}((L+m^{-1}H)^{\mathrm{An}}) \]
for any $m\in \mathbb {Z}_{>0}$. Therefore, $\Gamma ^{\mathrm{An}}\in \mathrm{PSH}(L^{\mathrm{An}})$ by proposition 22.1.74. $\square$
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