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22.1.101 The comparison theoremF1438A60D3D4

Let $X$ be a connected projective manifold of dimension $n$. Let $L$ be a pseudo-effective $\mathbb {Q}$-line bundle on $X$ and $h$ be a Hermitian metric on $L$ with $\theta =c_1(L,h)$.

Thanks to corollary 22.1.100, we already have a map

E99D2AFA897E 22.1.102
\begin{equation} \mathrm{PSH}^{\mathrm{NA}}(X,\theta )\rightarrow \mathrm{PSH}(L^{\mathrm{An}}),\quad \Gamma \mapsto \Gamma ^{\mathrm{An}}. \end{equation}

We observe that for $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and a Kähler form $\omega $ on $X$, we have

DB2DA874FB8C 22.1.103
\begin{equation} \left( P_{\theta +\omega }\left[ \Gamma \right]_{\mathcal{I}} \right)^{\mathrm{An}}=\Gamma ^{\mathrm{An}}. \end{equation}

Also observe that

F161F9E1E0FA 22.1.104
\begin{equation} \Gamma _{\max }=\Gamma ^{\mathrm{An}}(v_{\mathrm{triv}}), \end{equation}

Lemma 22.1.105.CB69CB164255 The map (22.1.102) is order preserving. Moreover, suppose that $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfies that $\Gamma ^{\mathrm{An}}\leq \Gamma '^{\mathrm{An}}$, then $\Gamma \leq \Gamma '$.

In particular, the map (22.1.102) is injective.

Proof. The map (22.1.102) is order preserving by definition. Let us take $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ with $\Gamma ^{\mathrm{An}}\leq \Gamma '^{\mathrm{An}}$. Fix a Kähler form $\omega $ on $X$.

Let $v\in X^{\operatorname{div}}$ and $t \in \mathbb {Q}_{>0}$. Then, using (22.1.83) and the homogeneity of divisorial valuations, we notice that

99B9B27CF451 22.1.106
\begin{equation} t \Gamma ^\mathrm{An}\left(t^{-1} v \right) = \sup _{\tau \in \mathbb {R}}\left( \left(\Gamma _{\tau }^{\theta +\omega }\right)^{\mathrm{An}}(v)+ t \tau \right). \end{equation}

A similar equality holds for $\Gamma '$. Therefore, by corollary 21.11.26, we have

\[ \left(\Gamma _{\tau }^{\theta +\omega }\right)^{\mathrm{An}}\leq \left(\Gamma '{}_{\tau }^{\theta +\omega }\right)^{\mathrm{An}} \]

for all $\tau \in \mathbb {R}$. It follows that

\[ \Gamma _{\tau }^{\theta +\omega }\preceq _{\mathcal{I}} \Gamma '{}_{\tau }^{\theta +\omega } \]

by proposition 16.8.9. Since both sides are $\mathcal{I}$-model, proposition 16.8.17 gives

\[ \Gamma _{\tau }^{\theta +\omega }\leq \Gamma '{}_{\tau }^{\theta +\omega } \]

for all $\tau \in \mathbb {R}$. Hence $\Gamma \leq \Gamma '$ by the definition of the order. $\square$

Lemma 22.1.107.AB6A7C1FD159 Let $\phi \in \mathcal{H}^{\mathrm{gf}}_{\mathbb {Q}}(L^{\mathrm{An}})$. Then there is a piecewise linear curve $A$ in $\mathrm{PSH}(X,\theta )$ with $\phi =A^{\mathrm{An}}$. In particular, $\phi $ is in the image of (22.1.102).

Note that from the proof below, the test curve $\Gamma $ corresponding to $\phi $ satisfies the following: For any $\tau \leq \Gamma _{\max }$, $\Gamma _{\tau }$ is elementary. See definition 16.8.20 for the definition of elementary metrics.

Proof. Let us write

C18150DD4B94 22.1.108
\begin{equation} \phi =\frac{1}{m}\max _{i=1,\ldots ,M} \left(\log |s_ i|+\lambda _ i\right), \end{equation}

where $m\in \mathbb {Z}_{>0}$, $s_{1},\ldots , s_ M$ are a finite number of sections of $L^ m$ and $\lambda _1,\ldots ,\lambda _ M\in \mathbb {Q}$.

Write $I_{\tau }$ for the set of $i$ such that $m^{-1}\lambda _ i=\tau $. We denote the finitely many $\tau $ so that $I_{\tau }$ is non-empty as $\tau _0> \cdots > \tau _ N$. For each $i=0,\ldots ,N$, we write

\[ A_{\tau _ i}=\frac{1}{m}\max _{j\in I_{\tau _ i}} \log |s_ j|^2_{h^ m}. \]

We define $A$ as the piecewise linear curve associated with the $A_{\tau _ i}$'s and the $\tau _ i$'s. For every $v\in X^{\mathrm{An}}$,

\[ A^{\mathrm{An}}(v)=\max _{i=0,\ldots ,N}\left(A_{\tau _ i}^{\mathrm{An}}(v)+\tau _ i\right) =\frac{1}{m}\max _{j=1,\ldots ,M}\left(\log |s_ j|(v)+\lambda _ j\right)=\phi (v), \]

where we used the convention $\log |s_ j|(v)=-v(s_ j)$.

The final assertion follows from 22.1.89 and theorem 22.1.72. $\square$

Proposition 22.1.109.9F673331DE01 Let $(\Gamma _ i)_{i\in I}$ be a decreasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. Assume that (22.1.42) is satisfied. Then

\[ \left( \inf _{i\in I} \Gamma _{i} \right)^{\mathrm{An}}=\inf _{i\in I} \Gamma _{i}^{\mathrm{An}}. \]

Proof. Take a Kähler form $\omega $ on $X$. We need to show that

\[ \left( \inf _{i\in I} P_{\theta +\omega }[\Gamma _ i]_{\mathcal{I}} \right)^{\mathrm{An}}=\inf _{i\in I} \Gamma _{i}^{\mathrm{An}}. \]

Therefore, after replacing $\theta $ by $\theta +\omega $, we may assume that $\Gamma _ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$ for all $i\in I$ and $\inf _{i\in I}\Gamma _ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$. Fix $v\in X^{\operatorname{div}}$. By theorem 22.1.72, it suffices to prove that

115AEB4414B4 22.1.110
\begin{equation} \sup _{\tau \in \mathbb {R}} \left( \left(\inf _{i\in I}\Gamma _{i,\tau }\right)^{\mathrm{An}}(v)+\tau \right)= \adjustlimits \inf _{i\in I}\sup _{\tau \in \mathbb {R}} \left( \Gamma _{i,\tau }^{\mathrm{An}}(v)+\tau \right). \end{equation}

Write $\Gamma =\inf _{i\in I}\Gamma _ i$. We first compare the two sides inside the Legendre-type supremum. If $\tau <\Gamma _{\max }$, then by the definition of the infimum test curve,

\[ \Gamma _{\tau }=\inf _{i\in I}\Gamma _{i,\tau }. \]

The net $(\Gamma _{i,\tau })_ i$ decreases to $\Gamma _{\tau }$. By 17.15.41, $\Gamma _{\tau }$ is stable under $P_{\theta }[\bullet ]$. Hence proposition 16.4.4 gives convergence of the masses, and corollary 16.9.14 yields

\[ \Gamma _{i,\tau }\xrightarrow {d_ S}\Gamma _{\tau }. \]

Hence theorem 16.9.55 gives

\[ \Gamma _{\tau }^{\mathrm{An}}(v)=\inf _{i\in I}\Gamma _{i,\tau }^{\mathrm{An}}(v),\quad \tau <\Gamma _{\max }. \]

If $\tau >\Gamma _{\max }$, then $\Gamma _{\tau }\equiv -\infty $, and also $\inf _ i\Gamma _{i,\tau }\equiv -\infty $, since $\Gamma _{\max }=\inf _ i(\Gamma _ i)_{\max }$. Thus the same equality holds for $\tau >\Gamma _{\max }$ as well, with value $-\infty $. The possible endpoint $\tau =\Gamma _{\max }$ does not affect the supremum: for any test curve $\Lambda $ and any $v\in X^{\operatorname{div}}$,

\[ \sup _{\tau \leq \Lambda _{\max }}\left(\Lambda _{\tau }^{\mathrm{An}}(v)+\tau \right) =\sup _{\tau < \Lambda _{\max }}\left(\Lambda _{\tau }^{\mathrm{An}}(v)+\tau \right), \]

because $\Lambda _{\Lambda _{\max }}\leq \Lambda _{\tau }$ for $\tau <\Lambda _{\max }$, hence

\[ \Lambda _{\Lambda _{\max }}^{\mathrm{An}}(v)+\Lambda _{\max } \leq \Lambda _{\tau }^{\mathrm{An}}(v)+\Lambda _{\max } \]

and we let $\tau \nearrow \Lambda _{\max }$.

Consequently, in (22.1.110) we may replace $\left(\inf _ i\Gamma _{i,\tau }\right)^{\mathrm{An}}(v)$ by $\inf _ i\Gamma _{i,\tau }^{\mathrm{An}}(v)$ inside the supremum. The equality then follows from proposition 21.11.36 applied to the closed convex functions $-\Gamma _{i,\bullet }^{\mathrm{An}}(v)$. $\square$

Proof. The map (22.1.102) is an order preserving injection by 22.1.105. It remains to prove that it is surjective. Let $\phi \in \mathrm{PSH}(L^{\mathrm{An}})$. We want to construct $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ with $\Gamma ^{\mathrm{An}}=\phi $.

Let $H$ be an ample line bundle and $(\epsilon _ i)_ i$ be a decreasing sequence of rational numbers with limit $0$, $\phi _ i\in \mathcal{H}^{\mathrm{gf}}_{\mathbb {Q}}((L+\epsilon _ i H)^{\mathrm{An}})$ such that

\[ \phi =\inf _{i>0}\phi _ i. \]

The existence of these data is guaranteed by theorem 22.1.75. Fix a Kähler form $\omega \in c_1(H)$.

Thanks to 22.1.107, we can find $\Gamma ^ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta +\epsilon _ i \omega )$ with $(\Gamma ^ i)^{\mathrm{An}}=\phi _ i$. It follows from 22.1.105 that

\[ \Gamma ^ i\geq P_{\theta +\epsilon _ i\omega }\left[ \Gamma ^{i+1} \right]_{\mathcal{I}} \geq \Gamma ^{i+1}. \]

Therefore, for any $\omega '\in \textup{Käh}(X)$, after discarding finitely many $i$ so that $\omega '\geq \epsilon _ i\omega $, the sequence $(P_{\theta +\omega '}\left[ \Gamma ^{i} \right]_{\mathcal{I}})_ i$ is decreasing. This does not change its infimum. We let

\[ \Gamma ^{\theta +\omega '}=\inf _{i\gg 1}P_{\theta +\omega '}\left[ \Gamma ^{i} \right]_{\mathcal{I}}\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta +\omega '). \]

Note that the infimum is defined thanks to (22.1.104). It follows from proposition 22.1.109 that

\[ \left(\Gamma ^{\theta +\omega '} \right)^{\mathrm{An}}=\phi . \]

From this, we conclude that for $\omega ',\omega ''\in \textup{Käh}(X)$ with $\omega '\leq \omega ''$, we have

\[ P_{\theta +\omega ''}\left[ \Gamma ^{\theta +\omega '}\right]_{\mathcal{I}}=\Gamma ^{\theta +\omega ''}. \]

Indeed, both sides have analytification $\phi $, by (22.1.103) and (22.1.102). The injectivity part of 22.1.105 gives our assertion.

It follows that $(\Gamma ^{\theta +\omega '})_{\omega '\in \textup{Käh}(X)}$ defines an element $\Gamma $ in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\Gamma ^{\mathrm{An}}=\phi $. $\square$

Theorem 22.1.112.CB40FF867A00 Under the bijection theorem 22.1.111, the operations on the space $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ defined in subsection 22.1.20 all correspond to the corresponding operations on $\mathrm{PSH}(L^{\mathrm{An}})$ in Boucksom–Jonsson's theory.

The meaning is immediate for all operations except for the trace operator, and the proofs are elementary, as we have seen in proposition 22.1.109 for the infimum operator. We shall only restate and prove the case of trace operators; the remaining arguments are recorded in [Xia23Operations].

Theorem 22.1.113.D613676A36CA Let $Y\subseteq X$ be an irreducible analytic subset. Consider an element $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ with well-defined restriction to $Y$. Then

0C743FB2F354 22.1.114
\begin{equation} \operatorname{Tr}_ Y(\Gamma )^{\mathrm{An}}|_{Y^{\operatorname{div}}}=\Gamma ^{\mathrm{An}}|_{Y^{\operatorname{div}}}. \end{equation}
Observe that there is a canonical identification $Y^{\operatorname{div}}=\widetilde{Y}^{\operatorname{div}}$. Recall that a generalized Fubini–Study metric is defined in definition 5.20.15.

Proof. We first reduce to the positive mass case. Choose a Kähler form $\omega _0$ on $X$ and set $\widehat{\Gamma }=P_{\theta +\omega _0}[\Gamma ]_{\mathcal{I}}$. Replacing $\theta $ by $\theta +\omega _0$ and $\Gamma $ by $\widehat{\Gamma }$ does not change $\Gamma ^{\mathrm{An}}$, by (22.1.103); it also only replaces $\operatorname{Tr}_ Y(\Gamma )$ by the corresponding $\mathcal{I}$-projection on $\widetilde{Y}$, whose analytification is unchanged. Hence we may assume that $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$. Let $\phi =\Gamma ^{\mathrm{An}}\in \mathrm{PSH}(L^{\mathrm{An}})$. By 22.1.116, $\phi (v_{Y,\mathrm{triv}})\neq -\infty $.

Take an ample line bundle $S$ on $X$ and a Kähler form $\omega $ in $c_1(S)$. Write $\phi $ as the decreasing limit of a sequence $(\phi ^{i})_ i$ of elements in $\mathcal{H}^{\mathrm{gf}}_{\mathbb {Q}}((L+i^{-1}S)^{\mathrm{An}})$ as in theorem 22.1.75.

Take $\Gamma ^{i}\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta +i^{-1}\omega )$ such that $\Gamma ^{i,\mathrm{An}}=\phi ^{i}$. Note that by 22.1.10, $\Gamma ^ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta +i^{-1}\omega )_{>0}$.

Write $\widehat{\Gamma }^ i\coloneqq P_{\theta +\omega }[\Gamma ^ i]_{\mathcal{I}}$ and $\widehat{\Gamma }\coloneqq P_{\theta +\omega }[\Gamma ]_{\mathcal{I}}$. Applying proposition 22.1.109 to the decreasing sequence $(\widehat{\Gamma }^ i)_ i$ and then using the injectivity in 22.1.105, we get $\inf _ i\widehat{\Gamma }^ i=\widehat{\Gamma }$. Hence, by the componentwise definition of this infimum, for any $\tau <\Gamma _{\max }$, we have

\[ \inf _{i\in \mathbb {N}}\widehat{\Gamma }^{i}_{\tau }=\widehat{\Gamma }_{\tau }. \]

Now proposition 16.4.4 and corollary 16.9.14 give

\[ \widehat{\Gamma }^{i}_{\tau }\xrightarrow {d_ S} \widehat{\Gamma }_{\tau }. \]

for all $\tau <\Gamma _{\max }$.

By 22.1.116 again, each $\widehat{\Gamma }^{i}$ has non-trivial restriction to $Y$. By proposition 20.2.22, for any Kähler form $\omega '$ on $\widetilde{Y}$ satisfying $\omega '\geq \omega |_{\widetilde{Y}}$ we have

\[ \operatorname{Tr}_ Y \left( \widehat{\Gamma }^{i}_{\tau } \right)\xrightarrow {d_ S} \operatorname{Tr}_ Y \left( \widehat{\Gamma }_{\tau }\right) \]

for any $\tau <(\operatorname{Tr}_ Y(\Gamma ))_{\max }$. Thanks to theorem 16.9.55, for every $c\operatorname{ord}_ F\in Y^{\operatorname{div}}$ and every such $\tau $,

\[ \operatorname{Tr}_ Y \left( \widehat{\Gamma }_{\tau } \right)^{\mathrm{An}}(c\operatorname{ord}_ F)=\inf _{i\geq 1}\operatorname{Tr}_ Y \left( \widehat{\Gamma }^{i}_{\tau } \right)^{\mathrm{An}}(c\operatorname{ord}_ F). \]

Applying proposition 21.11.36 to the Legendre transforms in $\tau $, and using again that $\mathcal{I}$-projection does not change analytification, we get

\[ \operatorname{Tr}_ Y(\Gamma )^{\mathrm{An}}(c\operatorname{ord}_ F)=\inf _{i\geq 1}\operatorname{Tr}_ Y(\Gamma ^ i)^{\mathrm{An}}(c\operatorname{ord}_ F). \]

Since also $\Gamma ^{\mathrm{An}}=\inf _ i \Gamma ^{i,\mathrm{An}}$, it suffices to prove (22.1.114) with $\Gamma ^ i$ in place of $\Gamma $.

In other words, we have reduced to the case where $\phi \in \mathcal{H}^{\mathrm{gf}}_{\mathbb {Q}}(L^{\mathrm{An}})$ and $L$ is big.

Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$ with $\Gamma ^{\mathrm{An}}=\phi $. By 22.1.107, we can find a concave curve $(\Gamma '_{\tau })_{\tau \leq \Gamma _{\max }}$ such that $\Gamma '_{\tau }$ is a generalized Fubini–Study metric for each $\tau \leq \Gamma _{\max }$ and such that

\[ \Gamma _{\tau }=P_{\theta }[\Gamma '_{\tau }]_{\mathcal{I}}=P_{\theta }[\Gamma '_{\tau }]. \]

Here the second equality follows from example 18.1.10, since generalized Fubini–Study metrics have analytic singularities. With the convention that $\operatorname{Tr}_ Y(-\infty )=-\infty $ and $(-\infty )^{\mathrm{An}}\equiv -\infty $, it follows that for any $c\operatorname{ord}_ F\in \widetilde{Y}^{\operatorname{div}}$,

\[ \begin{aligned} \phi |_{Y^{\mathrm{An}}}(c\operatorname{ord}_ F)=& \sup _{\tau <\Gamma _{\max }} \left(\Gamma '_{\tau }{}^{\mathrm{An}}(c\operatorname{ord}_ F)+\tau \right)\\ =& \sup _{\tau <\Gamma _{\max }} \left(\left(\Gamma '_{\tau }|_{\widetilde{Y}}\right)^{\mathrm{An}}(c\operatorname{ord}_ F)+\tau \right)\\ =& \sup _{\tau <\Gamma _{\max }} \left(\operatorname{Tr}_ Y(\Gamma '_{\tau })^{\mathrm{An}}(c\operatorname{ord}_ F)+\tau \right)\\ =& \sup _{\tau <\Gamma _{\max }} \left(\operatorname{Tr}_ Y(\Gamma _{\tau })^{\mathrm{An}}(c\operatorname{ord}_ F)+\tau \right)\\ =& \operatorname{Tr}_ Y(\Gamma )^{\mathrm{An}}(c\operatorname{ord}_ F). \end{aligned} \]

The third equality follows from example 20.2.15, since $\Gamma '_{\tau }$ has analytic singularities. The fourth equality follows from $\Gamma _{\tau }=P_{\theta }[\Gamma '_{\tau }]$, proposition 20.2.21 and corollary 16.8.14. It remains to justify the second line. Namely, we want to show that for any generalized Fubini–Study metric $\varphi $ whose restriction to $\widetilde{Y}$ is not identically $-\infty $, we have

8B0003DFBC94 22.1.115
\begin{equation} \varphi ^{\mathrm{An}}(c\operatorname{ord}_ F)=\left(\varphi |_{\widetilde{Y}}\right)^{\mathrm{An}}(c\operatorname{ord}_ F). \end{equation}

We can immediately reduce to the case where $\varphi $ is a Fubini–Study metric, and then to the case

\[ \varphi =\log |s|_{h_0}^2, \]

where $s$ is a holomorphic section of $L$, not vanishing identically on $Y$, in which case (22.1.115) is obvious. $\square$

Lemma 22.1.116.1861C279EAB7 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $Y\subseteq X$ be an irreducible analytic subset. Then the following are equivalent:

  1. C8E4B53ADBE1

    $\Gamma ^{\mathrm{An}}(v_{Y,\mathrm{triv}})\neq -\infty $;

  2. 9BDEAFBEB2AD

    $\Gamma ^{\mathrm{An}}|_{Y^{\mathrm{An}}}\not\equiv -\infty $;

  3. EB5674CDC803

    $\Gamma $ has a well-defined restriction to $Y$.

Here $v_{Y,\mathrm{triv}}$ denotes the trivial valuation of $\mathbb {C}(Y)$.

Proof. The equivalence between 1 and 2 is a simple consequence of the maximum principle [Lemma 1.4(i), BJ22].

To see the equivalence between 1 and 3, it suffices to observe that for any $\varphi \in \mathrm{PSH}(X,\theta )$,

\[ \varphi ^{\mathrm{An}}(v_{Y,\mathrm{triv}})= \begin{cases} -\infty ,& \textup{if }\nu (\varphi ,Y)>0;\\ 0,& \textup{if }\nu (\varphi ,Y)=0. \end{cases} \]

This completes the proof. $\square$

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