Definition 22.1.21.DA2917901B54 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$. We say $\Gamma \leq \Gamma '$ if for some $\omega \in \textup{Käh}(X)$, we have
22.1.20 Operations on non-Archimedean metricsC20FEECB51B7
Let $X$ be a connected compact Kähler manifold of dimension $n$ and $\theta ,\theta ',\theta ''$ be closed real smooth $(1,1)$-forms on $X$ representing big cohomology classes.
This section relies heavily on section 17.15. We shall use the notions introduced in that section without further explanations.
Proposition 22.1.22.8C5A487B9CCC Let $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\omega $ be a closed smooth positive $(1,1)$-form on $X$. Then the following are equivalent:
A1B3616B9907$\Gamma \leq \Gamma '$;
3EAAE9BE6F17$P_{\theta +\omega }[\Gamma ]_{\mathcal{I}}\leq P_{\theta +\omega }[\Gamma ']_{\mathcal{I}}$.
Proof. This follows immediately from 17.15.3. $\square$
Observe that this definition coincides with the corresponding definition in definition 17.15.1 when $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$.
Proposition 22.1.23.F7D709A21AE1 Let $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. Assume that $\Gamma \leq \Gamma '$. Then
Proof. It suffices to show that for any Kähler form $\omega $ on $X$, we have
which is an immediate consequence of theorem 13.13.11. $\square$
Definition 22.1.24.93939D1E527C Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$. Then we define $\Gamma +\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta +\theta ')$ as the unique element such that for any $\omega \in \textup{Käh}(X)$, we have
Proposition 22.1.25.06DFF1DE1519 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$. Suppose that $\omega ,\omega '$ are two smooth closed positive $(1,1)$-forms on $X$. Then
Proof. This is a direct consequence of 17.15.9. $\square$
Proposition 22.1.26.E9E94041F68D The operation $+$ is commutative and associative: For any $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$ and $\Gamma ''\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta '')$, we have
Proof. This is a direct consequence of proposition 17.15.7. $\square$
Definition 22.1.27.D1E32864F8F0 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $C\in \mathbb {R}$. We define $\Gamma +C\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ as the unique element such that for any $\omega \in \textup{Käh}(X)$, we have
Proposition 22.1.28.ECFDC5EDD4F2 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $C\in \mathbb {R}$. Suppose that $\omega $ is a smooth closed positive $(1,1)$-form on $X$. Then
Proof. This is clear by definition. $\square$
Proposition 22.1.29.87CB041BFCA3 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$ and $C,C'\in \mathbb {R}$. Then
80F4957A059F$(\Gamma +\Gamma ')+C=\Gamma +(\Gamma '+C)=(\Gamma +C)+\Gamma '$;
036FE960D3D0$\Gamma +(C+C')=(\Gamma +C)+C'$.
Proof. This is a direct consequence of proposition 17.15.11. $\square$
Proposition 22.1.30.11099644479B Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $C\in \mathbb {R}$. Then
Proof. It suffices to show that for each Kähler form $\omega $ on $X$,
which is obvious. $\square$
Definition 22.1.31.B819F1A85E09 Let $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, we define $\Gamma \lor \Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ as the unique element such that for any $\omega \in \textup{Käh}(X)$, we have
Proposition 22.1.32.9CACCE9D7690 Let $\Gamma ,\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\omega $ be a closed smooth positive $(1,1)$-form on $X$. Then
Proof. This is a direct consequence of 17.15.19. $\square$
Proposition 22.1.33.04004F65B932 The operation $\lor $ is commutative and associative.
Proof. This is a direct consequence of corollary 17.15.17. $\square$
Definition 22.1.34.C172DAF1B3E6 Let $(\Gamma ^ i)_{i\in I}$ be a non-empty family in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. Assume that
Then we define $\operatorname *{sup}_{i\in I}{}\! {}^{*}\Gamma ^ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ as the unique element such that for any $\omega \in \textup{Käh}(X)$, we have
Proposition 22.1.36.74CC0BF97B41 Let $(\Gamma ^ i)_{i\in I}$ be a non-empty family in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.35). Assume that $\omega $ is a closed smooth positive $(1,1)$-form on $X$. Then
Proof. This is a direct consequence of 17.15.30. $\square$
Proposition 22.1.37.21737B0303A5 Let $(\Gamma ^ i)_{i\in I}$ be a non-empty family in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.35). Then there exists a countable subfamily $I'\subseteq I$ such that
Proof. Fix a Kähler form $\omega _0$ on $X$. For each $m\geq 1$, proposition 17.15.31 gives a countable subfamily $I_ m\subseteq I$ such that
Set $I'=\bigcup _{m\geq 1}I_ m$. This is countable. We claim that it works.
Let $\omega '\in \textup{Käh}(X)$. Choose $m$ so large that $\omega '\geq m^{-1}\omega _0$. By proposition 22.1.36 and the compatibility of the transition maps,
Thus the two non-Archimedean metrics have the same component in every class $\theta +\omega '$, and the assertion follows. $\square$
Proposition 22.1.38.938848E420F9 Let $(\Gamma ^ i)_{i\in I}$ be a non-empty family in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.35). Let $C\in \mathbb {R}$. Then
Suppose that $(\Gamma '^ i)_{i\in I}$ is another family in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$ satisfying (22.1.35). Suppose that $\Gamma ^ i\leq \Gamma '^ i$ for all $i\in I$. Then
Proof. This is an immediate consequence of proposition 17.15.32. $\square$
Proposition 22.1.39.15E20104530B Let $(\Gamma ^ i)_{i\in I}$ be an increasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.35). Then
AA5696D80091
22.1.40
Proof. The $\geq $ direction in (22.1.40) is a direct consequence of proposition 22.1.23. It remains to prove the reverse inequality.
Note that (22.1.40) holds when $\operatorname{vol}\Gamma ^ i>0$ for each $i\in I$, as a consequence of proposition 17.15.22, corollary 16.9.12 and theorem 16.9.57.
In particular, for each Kähler form $\omega $ on $X$, we have
For our purpose, we need to show that for any $\epsilon >0$, we can find $\omega $ so that
We shall show that it is possible to choose $\omega $ so that the stronger statement holds:
Equivalently, we need to choose $\omega $ so that for any Kähler form $\omega '$ on $X$ dominated by $\omega $, we have
Fix a Kähler form $\omega _0$ on $X$ and a Kähler form $\Omega $ such that $\Omega \geq \theta +\omega _0$. It is enough to take $\omega =\delta \omega _0$ for some $\delta \in (0,1)$. If $\omega '$ is dominated by $\omega $, then $\theta +\omega '\leq \Omega $. Set
By the transition compatibility and proposition 17.12.19, the potential $\Gamma ^{i,\theta +\omega }_{-\infty }$ has the same $P$-singularity type in the class $\theta +\omega $ as $\Gamma ^{i,\theta +\omega '}_{-\infty }$. Hence its mass can be computed as
Therefore,
In the last inequality we used the facts that $0\leq \omega -\omega '\leq \omega $ and $\theta +\omega '\leq \Omega $, and the monotonicity theorem theorem 13.13.11. We can choose $\omega $ so that the right-hand side is less than $\epsilon /2$. Our assertion then follows. $\square$
Definition 22.1.41.65E2E07550F1 Let $(\Gamma ^ i)_{i\in I}$ be a decreasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. Assume that
then we define $\inf _{i\in I}\Gamma ^ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ as the unique element such that for each $\omega \in \textup{Käh}(X)$, we have
341067287939
22.1.43
This follows from proposition 17.15.40. Moreover, by 17.15.41, we have $\inf _{i\in I}\Gamma ^ i\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, and this definition extends definition 17.15.37.
In general,
as a consequence of proposition 22.1.23. But the reverse inequality fails in general.
Proposition 22.1.44.07B251D899EF Let $(\Gamma ^ i)_{i\in I}$ be a decreasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.42). Assume that $\omega $ is a closed smooth positive $(1,1)$-form on $X$. Then
Proof. This follows from 17.15.41. $\square$
Proposition 22.1.45.C8734FD15163 Let $(\Gamma ^ i)_{i\in I}$ be a decreasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.42). Let $C\in \mathbb {R}$. Then
Suppose that $(\Gamma '^ i)_{i\in I}$ is another decreasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$ satisfying (22.1.42). Suppose that $\Gamma ^ i\leq \Gamma '^ i$ for all $i\in I$. Then
Proof. This is clear by definition. $\square$
Definition 22.1.46.EB1311598A32 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\lambda \in \mathbb {R}_{>0}$. Then we define $\lambda \Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\lambda \theta )$ as the unique element such that for any $\omega \in \textup{Käh}(X)$, we have
Proposition 22.1.47.68FB6124EEB2 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\lambda \in \mathbb {R}_{>0}$. Then for any closed smooth positive $(1,1)$-form $\omega $ on $X$, we have
Proof. This follows immediately from 17.15.36. $\square$
Proposition 22.1.48.EDFB2682E78E Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, $\Gamma '\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta ')$, $C\in \mathbb {R}$ and $\lambda ,\lambda '>0$, we have
Suppose that $(\Gamma ^ i)_{i\in I}$ is a non-empty family in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.35). Then
If $(\Gamma ^ i)_{i\in I}$ is a decreasing net in $\mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ satisfying (22.1.42), then
Proof. Everything except the last assertion follows from proposition 17.15.35. The last assertion follows directly from the definition. $\square$
Proposition 22.1.49.1743F9AEA475 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ and $\lambda \in \mathbb {R}_{>0}$. Then
Proof. This is clear by definition. $\square$
Definition 22.1.50.C0E37055D126 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. Let $Y\subseteq X$ be an irreducible analytic subset. We say that the trace operator of $\Gamma $ along $Y$ is well-defined if
for all sufficiently negative $\tau $ and every $\omega \in \textup{Käh}(X)$. We define
Here $\omega $ is any Kähler form on $X$; this number is independent of the choice of $\omega $ by the compatibility of the transition maps.
In this case, we define $\operatorname{Tr}_ Y(\Gamma )\in \mathrm{PSH}^{\mathrm{NA}}(\widetilde{Y},\theta |_{\widetilde{Y}})$3 as the unique element such that for any $\omega \in \textup{Käh}(\widetilde{Y})$, the component
6697E3349082
22.1.51
is defined as follows:
5517A8C43D97We let
284D786E2B4E22.1.52\begin{equation} \left( \operatorname{Tr}_ Y(\Gamma )^{\theta |_{\widetilde{Y}}+\omega } \right)_{\max }=\left(\operatorname{Tr}_ Y(\Gamma )\right)_{\max }; \end{equation}E0B260D169B4for each $\tau \in \mathbb {R}$ less than $\left(\operatorname{Tr}_ Y(\Gamma )\right)_{\max }$, we define
\[ \operatorname{Tr}_ Y(\Gamma )^{\theta |_{\widetilde{Y}}+\omega }_{\tau }\coloneqq P_{\theta |_{\widetilde{Y}}+\omega }\left[ \operatorname{Tr}_ Y^{\theta +\tilde{\omega }}\left(\Gamma ^{\theta +\tilde{\omega }}_{\tau }\right) \right]_{\mathcal{I}}, \]where $\tilde{\omega }$ is an arbitrary Kähler form on $X$ such that $\omega \geq \tilde{\omega }|_{\widetilde{Y}}$.
Proposition 22.1.53.E7009D90BCC6 Let $\pi \colon Y\rightarrow X$ be a proper bimeromorphic morphism from a compact Kähler manifold $Y$. Then all definitions in this section are invariant under pullback to $Y$.
The relevant notations are summarized in the following diagram:
Proof. We only prove the assertion for the trace operator, as the other proofs are similar.
We shall use the notations above. Observe that for any closed positive smooth $(1,1)$-form $\omega $ on $X$ with positive mass, we have
and
Here we implicitly used proposition 22.1.17. Therefore,
Let $\tau \in \mathbb {R}$ be less than this common value. Take a Kähler form $\omega _{\widetilde{Z}}$ (resp. $\omega _{\widetilde{W}}$) on $\widetilde{Z}$ (resp. $\widetilde{W}$). Take a Kähler form $\omega _ Y$ on $Y$ (resp. $\omega _ X$ on $X$) such that
We want to show that, after projection to the common background $(\pi ^*\theta )|_{\widetilde{W}}+\omega _{\widetilde{W}}$,
Unfolding the definitions, we reduce to
Using proposition 20.2.21, this is equivalent to
This is a consequence of 20.2.24. $\square$
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