Lemma 16.28.33.A143B4417F78 The set $\mathcal J^{\mathrm{act}}_ a(\delta ,q)$ is nonempty, convex and compact. For $\delta ,\eta \geq \epsilon >0$ and $p,q\in C(K,\mathbb R)$,
FB1602967EA5
16.28.34
\begin{equation} |F_{\eta ,p}(a)-F_{\delta ,q}(a)| \leq \| p-q\| _\infty + |\eta -\delta |\left(V_ K^*(a)+ \frac{\operatorname {osc}_ Kq}{\epsilon }\right). \end{equation}
If $\delta _ j\to \delta >0$, $q_ j\to q$ uniformly and $(\mu _ j,c_ j)\in \mathcal J^{\mathrm{act}}_ a(\delta _ j,q_ j)$, then these pairs have a convergent subsequence, and every subsequential limit belongs to $\mathcal J^{\mathrm{act}}_ a(\delta ,q)$.
Proof.
Nonemptiness follows from theorem 16.28.27. Since the test functions are continuous, $\mathcal J_ a(K)$ is closed and convex, and the equality defining active pairs is a closed affine condition. For an active pair, (16.28.17), applied with the weight $q$, gives
\[ 0\leq c\leq \frac{F_{\delta ,q}(a)-\inf _ Kq}{\delta } \leq V_ K^*(a)+\frac{\operatorname {osc}_ Kq}{\delta }. \]
The pairs in $\mathcal J_ a(K)$ with bounded constants form a compact set, as in the proof of theorem 16.28.29; hence the set of active pairs is compact.
With $q$ fixed, lemma 16.28.18 and (16.28.17), applied with the weight $q$, bound $|F_{\eta ,q}(a)-F_{\delta ,q}(a)|$ by $|\eta -\delta |(V_ K^*(a)+\operatorname {osc}_ Kq/\epsilon )$. Comparison of obstacles and translation by constants bound $|F_{\eta ,p}(a)-F_{\eta ,q}(a)|$ by $\| p-q\| _\infty $. Adding these bounds gives (16.28.34).
For the sequence in the statement, the constants $c_ j$ have a common bound, by the estimate above, because the weights $q_ j$ are uniformly bounded and the parameters $\delta _ j$ are bounded below by a positive constant. Weak compactness of probability measures gives a convergent subsequence of pairs, and its limit belongs to $\mathcal J_ a(K)$, which is closed. The estimate (16.28.34) gives $F_{\delta _ j,q_ j}(a)\to F_{\delta ,q}(a)$, while uniform convergence of the $q_ j$ and weak convergence of the $\mu _ j$ give $\int _ Kq_ j\, \mathrm{d}\mu _ j\to \int _ Kq\, \mathrm{d}\mu $. Passing to the limit in the equality defining active pairs proves the last assertion.
$\square$
Comments
Corrections, questions, and mathematical discussion are welcome. Sign in with GitHub to comment. Comments are public.