Proposition 9.11.65.D0F33FF75830 There are a smooth real $(1,1)$-form $\alpha $ on $X$, mixing the factors $C$ and $E_2$, and a smooth real function $v_0$ on $Y$ such that, for every sufficiently small nonzero real $\varepsilon $, the Hermitian form $h=h_0+\varepsilon \alpha $ is not closed and
\[ \begin{gathered} H=\pi ^*h,\qquad k=H+\mathrm{dd}^{\mathrm{c}}v_0=K_0+\varepsilon \pi ^*\alpha \geq \tfrac 12K_0,\\ \mathrm{dd}^{\mathrm{c}}(H^ r)=\mathrm{dd}^{\mathrm{c}}(k^ r)=0\quad (r\geq 0). \end{gathered} \]
Moreover $\int _ YH^ n=\int _ Yk^ n=:M>0$.
Proof.
Choose real smooth functions $A$ on $C$, supported away from $q$, and $B$ on $E_2$. Let
\[ \alpha =\partial A\wedge \bar\partial B+\bar\partial A\wedge \partial B =\partial (A\bar\partial B)+\bar\partial (A\partial B). \]
The form $\alpha $ is real and satisfies $\mathrm{dd}^{\mathrm{c}}\alpha =0$. At a point where $\partial A=0$, $\partial \bar\partial A\ne 0$ and $\partial B\ne 0$,
\[ \partial \alpha =-\partial A\wedge \partial \bar\partial B +\partial \bar\partial A\wedge \partial B\ne 0. \]
Thus $\mathrm d\alpha \ne 0$. The form $\alpha $ vanishes near the singular locus. Its operator norm relative to $H_0$ is bounded on its support, and its norm relative to $K_0$ is bounded everywhere. Choose $|\varepsilon |$ so small that both norms, multiplied by $|\varepsilon |$, are less than $1/2$. This proves positivity of $h$ in the ambient sense, semipositivity of $H$, and the inequality $K_0+\varepsilon \pi ^*\alpha \geq \tfrac 12K_0$.
The equation $\partial _ z\partial _{\bar z}v=\lambda -\rho $ on $E_1$, whose right-hand side has mean zero, has a smooth real periodic solution, obtained by dividing its nonzero Fourier coefficients. Its pullback $v_0$ satisfies $\mathrm{dd}^{\mathrm{c}}v_0=(\lambda -\rho )\kappa _1$, which proves the formula for $k$. The forms $H_0$ and $K_0$ are closed. Hence $\mathrm dk$ and $\mathrm d^{\mathrm c}k$ come from the complex surface $E_1\times E_2$, so that $\mathrm dk\wedge \mathrm d^{\mathrm c}k=0$ for degree reasons, and $\mathrm{dd}^{\mathrm{c}}k=0$. The same identities hold for $H$. The Leibniz rule now gives $\mathrm{dd}^{\mathrm{c}}(k^ r)=\mathrm{dd}^{\mathrm{c}}(H^ r)=0$ for all $r$; this uses both torsion identities, not only pluriclosedness. Expanding $(H+\mathrm{dd}^{\mathrm{c}}v_0)^ n$ and integrating by parts shows that every term containing $\mathrm{dd}^{\mathrm{c}}v_0$ integrates to zero. Hence the masses agree, and positivity of $k$ makes them positive.
$\square$
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