We return to the blowup $\pi :X=\operatorname {Bl}_ Z Y\to Y$ of section 15.23. Here $(Y,h)$ is a compact Hermitian $n$-fold, the smooth center $Z$ has codimension $r\geq 2$, $E$ is the exceptional divisor with canonical section $s_ E$, $\Theta _ E$ is the curvature form of a smooth metric on $\mathcal O(E)$, $L=\log |s_ E|^2$, and the background is $\theta =\pi ^*h+c\Theta _ E$ with $c>0$. By proposition 15.23.2, every $u\in \mathrm{PSH}(X,\theta )$ has the form $u=cL+q\circ \pi +C$ with $q$ an $h$-plurisubharmonic function, and $u$ has minimal singularities exactly when $q$ is bounded; we then call $u$ a potential of minimal type. Fix a smooth positive volume form $\mathrm{d}V$ on $X$, and use adapted coordinates in which $\pi (y,z,w)=(y,z,zw)$ and $E=\{ z=0\} $.
Proposition 10.21.9.86DDC28E0989 Let $u\in \mathrm{PSH}(X,\theta )$ be of minimal type, and suppose that its residual current $S=(\theta +\mathrm{dd}^{\mathrm{c}}u)-c[E]$ extends smoothly and semipositively across $E$. Then, on smaller adapted charts, $0\leq S^ n/\mathrm{d} V\leq C|z|^{2(r-1)}$. Consequently, if the Monge–Ampère measure of $u$ has density $|z|^{2\ell }g$ with $g$ smooth and strictly positive, then $\ell \geq r-1$. This order condition is necessary but not sufficient for a smooth residual. In particular, in this background a smooth strictly positive density is incompatible with a smooth residual for a potential of minimal type.
Proof.
Write $u=cL+v$. Since $S=\pi ^*h+\mathrm{dd}^{\mathrm{c}}v$ is smooth, the distributional Laplacian of $v$ is smooth, and local elliptic regularity makes $v$ smooth. On each fiber of $E\to Z$, a compact projective space, $\pi ^*h$ restricts to zero and $\mathrm{dd}^{\mathrm{c}}v$ restricts to the semipositive form $S$; the maximum principle therefore makes $v$ constant on the fiber. Hence every vertical diagonal entry of $S$ is a smooth nonnegative function vanishing at $z=0$, and is therefore $O(|z|^2)$. The other diagonal entries are bounded, so Hadamard's determinant inequality gives the stated bound. The pullback $\pi ^*h$ attains this order, while the examples below show that the order condition is not sufficient. The argument does not apply to prescribed nonminimal singularities, whose residuals can be positive on the exceptional fibers.
$\square$
A singular Hessian, rather than a zero of the density, can also make a solution nonsmooth. The following local example has constant positive density and a potential that is not $C^1$, and it can be placed in a compact manifold.
Example 10.21.10.9F3252D2DC77 On a polydisk with coordinates $(z,w)\in \mathbb C\times \mathbb C^{n-1}$, $n\geq 2$, set $P(z,w)=|z|^{2/n}(1+|w|^2)$. Off $z=0$, its Hessian block in the $w$-directions is $|z|^{2/n}I$ and its normal Schur complement is $n^{-2}|z|^{2/n-2}$, so its Hessian determinant is the positive constant $n^{-2}$. Since $P$ is bounded, it extends across $z=0$ as a plurisubharmonic function whose Monge–Ampère measure has no additional mass on the divisor. Yet $P$ is not $C^1$ along that divisor.
This local example extends to a compact Kähler model on $\mathbb P^ n$. On an affine chart with coordinates $y=(z,w)$, the Fubini–Study form is $\omega _{\mathrm{FS}}=\mathrm{dd}^{\mathrm{c}}\log (1+|y|^2)$; for constants $\lambda >0$ and $B$, put $H=\lambda \log (1+|y|^2)$ and $Q=H-B$. Choose nested radii and the parameters so that $Q>P+2\epsilon $ on an outer collar of a ball and $Q<P-2\epsilon $ on an inner ball. A smooth convex regularized maximum $U=M_\epsilon (P,Q)$ then equals $P$ on the inner ball and $Q$ on the collar. Put $v=U-H$ on the ball and $v=-B$ outside it, so that $\lambda \omega _{\mathrm{FS}}+\mathrm{dd}^{\mathrm{c}}v$ equals $\mathrm{dd}^{\mathrm{c}}U$ on the ball and $\lambda \omega _{\mathrm{FS}}$ outside. This current is positive and smooth off $\{ z=0\} $; on the gluing annulus its density is at most $C|z|^{2/n-2}$, so it belongs globally to $L^ p$ for every $1<p<n/(n-1)$. On the inner ball the density is smooth and strictly positive, but the potential is not $C^1$. There the metric is comparable to $|z|^{2/n-2}|\mathrm{d} z|^2+|z|^{2/n}|\mathrm{d} w|^2$, and the distance to the divisor is of order $|z|^{1/n}$.
The construction also works on a Hopf manifold. Choose a global Hermitian form equal to $\mathrm{dd}^{\mathrm{c}}(\lambda |y|^2)$ on a coordinate ball and equal to a fixed nonclosed Hermitian form outside a slightly larger ball, using a convex interpolation of positive forms. Carry out the same regularized maximum with $H=\lambda |y|^2$ on the inner ball, and set $v=-B$ outside it. The background is still nonclosed on the outer region, and the local potential and density are unchanged. As in the projective case, the density is controlled globally only in $L^ p$.
This example does not contradict corollary 15.18.50. The density loses smoothness along the divisor $\{ z=0\} $ in the gluing region, so the polar set of an admissible barrier must contain that part of the divisor. Being analytic, it then also contains the continuation of the divisor into the inner ball. The corollary requires a smooth positive density on the entire regular locus of the barrier, and local smoothness of the density on the inner ball cannot replace this hypothesis.
On a blowup, a radial potential of power type produces densities with exceptional zeros or poles of every order. These examples show that the order condition in proposition 10.21.9 is not sufficient.
Example 10.21.11.554ACF84A13B Let $\pi :X=\operatorname {Bl}_0\mathbb P^ n\to \mathbb P^ n$ be the blowup at the origin of an affine chart with coordinates $y$, let $E$ be its exceptional divisor, and write $s=|y|^2$. For every $\gamma ,c>0$, one can choose $\lambda >0$ so that the background $\theta =\pi ^*(\lambda \omega _{\mathrm{FS}})+c\Theta _ E$ admits a potential $u=cL+q\circ \pi $ with bounded Hölder remainder $q$, hence of minimal type, whose total local potential $\lambda \log (1+s)+q$ equals $As^\gamma +B$ near the origin, for constants $A>0$ and $B\in \mathbb R$. To construct $q$, choose a smooth function $m$ with $m(s)>0$ and $m'(s)>0$, equal to $A\gamma s^\gamma $ near $s=0$ and to $\lambda s/(1+s)$ outside a slightly larger interval; taking $A$ small puts the values at the two ends in the right order. Match the positive derivative germs on narrow collars, fill the remaining positive deficit of the integral with a positive interior derivative and a bump, and integrate $U'=m/s$, choosing the constant so that $U(s)=\lambda \log (1+s)$ for large $s$. Set $q(y)=U(|y|^2)-\lambda \log (1+|y|^2)$ on the affine chart and extend it by zero outside. Since $m$ and $m'$ are positive, positivity holds throughout the compact interpolation region.
On the blowup, in coordinates with $y=(z,zw)$, the total local potential of $u$ is $A|z|^{2\gamma }(1+|w|^2)^\gamma +B$. The density of $u$ is $|z|^{2\ell }G$ with $G$ smooth and positive and $\ell =n\gamma -1>-1$, since the Hessian determinant of $A|y|^{2\gamma }$ is $A^ n\gamma ^{n+1}s^{n(\gamma -1)}$ and the squared Jacobian of the blowup is $|z|^{2(n-1)}$. The metric off $E$ is comparable to
D97EEB42728A
10.21.12
\begin{equation} |z|^{2\gamma -2}|\mathrm{d} z|^2+|z|^{2\gamma }|\mathrm{d} w|^2, \end{equation}
the distance to $E$ is of order $|z|^\gamma $, and the metric completion collapses $E$ to a point. If $\ell $ is a nonnegative integer, the density is smooth. At $\ell =0$ the density is smooth and strictly positive, but the remainder has exact normal Hölder exponent $2/n$ for $n>2$, is Lipschitz but not $C^1$ for $n=2$, and the normal coefficient of the metric is unbounded. For $-1<\ell <0$, the density belongs to $L^ p$ exactly when $p\ell >-1$. Taking $\ell =n$ gives a smooth density with a zero of order $2n\geq 2(n-1)$, while the residual Hessian remains nonsmooth; this proves the insufficiency asserted in proposition 10.21.9. A small nonclosed perturbation of the background supported away from the origin leaves these local calculations unchanged, and gives the same examples in a nonclosed background, with the Monge–Ampère measure of the perturbed potential as prescribed measure.
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