Definition 22.1.79.322D4668B967 For $\varphi \in \mathrm{PSH}(X,\theta )$, we define the analytification $\varphi ^{\mathrm{An}}\colon X^{\mathrm{An}}\rightarrow [-\infty ,0]$ as follows:
2CFF9C7C56DB
22.1.80
1630658F75F9Definition 22.1.79.322D4668B967 For $\varphi \in \mathrm{PSH}(X,\theta )$, we define the analytification $\varphi ^{\mathrm{An}}\colon X^{\mathrm{An}}\rightarrow [-\infty ,0]$ as follows:
2CFF9C7C56DB
22.1.80
Note that we can also write
DFFDD4E75B4D
22.1.81
When $v=t\operatorname{ord}_ E$ for some prime divisor $E$ over $X$, $\varphi ^{\mathrm{An}}(v)=-t\nu (\varphi ,E)$ by proposition 5.16.15.
Definition 22.1.82.866728488224 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$. We define the analytification $\Gamma ^{\mathrm{An}}\colon X^{\operatorname{div}}\rightarrow [-\infty ,\infty )$ of $\Gamma $ as follows: For any $\omega \in \textup{Käh}(X)$, we define
45957E422015
22.1.83
Note that (22.1.83) can be equivalently written as
with $(-\infty )^{\mathrm{An}}(v) = -\infty $ understood.
Proposition 22.1.84.A87B7BF0C3D5 Let $\Gamma \in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )_{>0}$ with $\Gamma _{\max }\leq 0$. Let $\Psi $ be the complexification of $\Gamma ^*$. Then
B5F5AD50A5AD
22.1.85
Proof. Recall that
By (22.1.69), we have $\sigma (v)(\log |\delta |^2)=1$ and $\sigma (v)(\Gamma _{\tau })=v(\Gamma _{\tau })$ for all $\tau \leq \Gamma _{\max }$. So we have
Lastly, since $\sigma (v)$ is a divisorial valuation on $X \times \Delta $, by corollary 5.16.9, we conclude (22.1.85). $\square$
Definition 22.1.86.54C62141C0D9 Let $N\in \mathbb {N}$, and $A_{0},\ldots ,A_ N$ be a finite collection of elements in $\mathrm{PSH}(X,\theta )$, and $\tau _0>\tau _1>\cdots >\tau _ N$ be finitely many real numbers. Then the piecewise linear curve $A=(A_{\tau })_{\tau \in \mathbb {R}}$ in $\mathrm{PSH}(X,\theta )\cup \{ -\infty \} $ associated with these data is the affine interpolation of these data:
FE3BE40BF529$A_{\tau _ i}=A_ i$ for $i=0,\ldots ,N$;
2D3D174A0348$A_{\tau }=A_{\tau _ N}$ for $\tau \leq \tau _ N$;
B0B44E5310EAfor $t\in (0,1)$ and $i=0,\ldots ,N-1$, we have
8FF2573D4019$A_{\tau }\equiv -\infty $ for $\tau >\tau _0$.
The analytification of $A$ is the function $A^{\mathrm{An}}\colon X^{\mathrm{An}}\rightarrow [-\infty ,\infty )$ defined as follows:
2B233D0F0F88
22.1.87
Remark 22.1.88.9911A537C86C Note that $\tau \mapsto A_{\tau }$ is upper semicontinuous, but not necessarily concave. Let $(A'_{\tau })_{\tau \in \mathbb {R}}$ be the upper concave envelope of $\tau \mapsto A_{\tau }$. Then it can be inductively constructed as follows:
D954EE804570For $\tau \in (\tau _0,\infty )$, we let $A'_{\tau }\equiv -\infty $;
34859AD723A6we set $A'_{\tau _0}=A_{\tau _0}$;
FCE6B95F3C1Fdefine inductively for $j=0,\ldots ,N-1$ the following: For $\tau \in [\tau _{j+1},\tau _ j)$, we set
E47ACD33228Bfor $\tau \in (-\infty ,\tau _ N)$, we set $A'_{\tau }=A_{\tau _ N}$.
This construction is just a reformulation of the general formula proposition 21.11.12.
In particular, $A'_{\tau }\in \mathrm{PSH}(X,\theta )$ for all $\tau \leq \tau _0$.
Note that $A'$ is not necessarily piecewise linear.
Lemma 22.1.89.6784060E951F Let $A$ be a piecewise linear curve in $\mathrm{PSH}(X,\theta )$. Let $(A'_{\tau })_{\tau \in \mathbb {R}}$ be the upper concave envelope of $\tau \mapsto A_{\tau }$. Define $\tilde A$ by
Then $\tilde A\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$, and
F46F1129051C
22.1.90
Proof. We continue to use the notations in definition 22.1.86. The fact that $\tilde{A}\in \mathrm{PSH}^{\mathrm{NA}}(X,\theta )$ follows from 22.1.88 and the cocycle property of the $\mathcal{I}$-projection. In order to prove (22.1.90), we fix $v\in X^{\operatorname{div}}$ and $\omega \in \textup{Käh}(X)$. The inductive construction in 22.1.88 uses only finite maxima and positive affine combinations of the potentials $A_{\tau _ i}$. On divisorial valuations, analytification commutes with both operations. Moreover, $P_{\theta +\omega }[\bullet ]_{\mathcal I}$ does not change divisorial valuations. Hence
is the ordinary upper concave envelope of $\tau \mapsto A_\tau ^{\mathrm{An}}(v)$. The Legendre-type supremum over $\tau $ is therefore unchanged by passing from $A$ to $A'$, which proves (22.1.90). $\square$
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