Proposition 5.16.15.8EFDC4A2C19E Let $\varphi \in \mathrm{PSH}(X)$ and $E$ be a prime divisor over $X$. Then
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5.16.16
\begin{equation} \nu (\varphi ,E)=\lim _{k\to \infty }\frac{1}{k}\operatorname{ord}_ E\mathcal{I}(k\varphi ). \end{equation}
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