Proof.
1 This follows from the symmetry of the mixed non-pluripolar product in (18.1.22), cf. proposition 13.11.4 2.
2 For each $i$ and each $\epsilon >0$, we have
\[ P_{\theta _ i}[\varphi _ i]_{\mathcal{I}}\sim _ P P_{\theta _ i+\epsilon \omega }\left[P_{\theta _ i}[\varphi _ i]_{\mathcal{I}}\right]_{\mathcal{I}}=P_{\theta _ i+\epsilon \omega }[\varphi _ i]_{\mathcal{I}} \]
as a consequence of example 18.1.11. Hence using proposition 16.8.22 and the multi-linearity of the non-pluripolar product proposition 13.11.4 6,
\[ \begin{aligned} & \lim _{\epsilon \to 0+}\operatorname{vol}(T_1+\epsilon \omega ,\ldots ,T_ n+\epsilon \omega )\\ =& \lim _{\epsilon \to 0+}\int _ X \left(\theta _1+\epsilon \omega +\mathrm{dd}^{\mathrm{c}}P_{\theta _1}[\varphi _1]_{\mathcal{I}}\right)\wedge \cdots \wedge \left(\theta _ n+\epsilon \omega +\mathrm{dd}^{\mathrm{c}}P_{\theta _ n}[\varphi _ n]_{\mathcal{I}}\right)\\ =& \operatorname{vol}(T_1,\ldots ,T_ n). \end{aligned} \]
3 We write $T_ i=\theta _ i+\mathrm{dd}^{\mathrm{c}}\varphi _ i$ as before for each $i$ and $T_1'=\theta _1'+\mathrm{dd}^{\mathrm{c}}\varphi _1'$. The potentials $P_{\theta _1}[\varphi _1]_{\mathcal I}$ and $P_{\theta _1'}[\varphi _1']_{\mathcal I}$ are $\mathcal I$-model with positive masses, hence $\mathcal I$-good. By proposition 18.1.17, their sum is $\mathcal I$-good. Moreover, it is $\mathcal I$-equivalent to $\varphi _1+\varphi _1'$. Then thanks to proposition 18.1.17,
\[ P_{\theta _1}[\varphi _1]_{\mathcal{I}}+P_{\theta _1'}[\varphi _1']_{\mathcal{I}}\sim _ P P_{\theta _1+\theta _1'}\left[P_{\theta _1}[\varphi _1]_{\mathcal{I}}+P_{\theta _1'}[\varphi _1']_{\mathcal{I}} \right]_{\mathcal{I}} = P_{\theta _1+\theta _1'}\left[\varphi _1+\varphi _1'\right]_{\mathcal{I}} \]
Thus by proposition 16.8.22, we have
\[ \begin{aligned} & \operatorname{vol}(T_1+T_1',T_2,\ldots ,T_ n)\\ =& \int _ X \left( \theta _1+\theta _1'+\mathrm{dd}^{\mathrm{c}}P_{\theta _1+\theta _1'}[\varphi _1+\varphi _1']_{\mathcal{I}} \right)\wedge \left( \theta _2+\mathrm{dd}^{\mathrm{c}}P_{\theta _2}[\varphi _2]_{\mathcal{I}}\right)\wedge \cdots \\ & \wedge \left( \theta _ n+\mathrm{dd}^{\mathrm{c}}P_{\theta _ n}[\varphi _ n]_{\mathcal{I}}\right)\\ =& \int _ X \left( \theta _1+\theta _1'+\mathrm{dd}^{\mathrm{c}}P_{\theta _1}[\varphi _1]_{\mathcal{I}}+\mathrm{dd}^{\mathrm{c}}P_{\theta _1'}[\varphi _1']_{\mathcal{I}} \right)\wedge \left( \theta _2+\mathrm{dd}^{\mathrm{c}}P_{\theta _2}[\varphi _2]_{\mathcal{I}}\right)\wedge \cdots \\ & \wedge \left( \theta _ n+\mathrm{dd}^{\mathrm{c}}P_{\theta _ n}[\varphi _ n]_{\mathcal{I}}\right)\\ =& \operatorname{vol}(T_1,T_2,\ldots ,T_ n)+\operatorname{vol}(T_1',T_2,\ldots ,T_ n). \end{aligned} \]
4 This follows from (18.1.22), proposition 16.6.27 1 and proposition 13.11.4 6.
5 Our assertion follows from the monotonicity theorem theorem 13.13.11.
$\square$
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