Proposition 14.24.5.25FABE38E60B There is a finite positive measure $E=\mathrm{d} w\wedge \mathrm d^{\mathrm c}w\wedge T$, defined below as a limit of regularizations, with the following properties.
For every smooth real function $\chi $ on $\mathbb R$,
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14.24.6
\begin{equation} \int _ X\chi ''(w)\, \mathrm{d} E=\int _ X\chi (w)\, \mathrm{dd}^{\mathrm{c}}T. \end{equation}
The signed current $\mathrm{dd}^{\mathrm{c}}T$ is a finite measure. If $a=\min _ Xw$, $b=\max _ Xw$, and
\[ k(t)=\int _ X(w-t)_+\, \mathrm{dd}^{\mathrm{c}}T, \]
then $k$ is nonnegative, globally Lipschitz, supported on $[a,b]$, and
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\begin{equation} w_*E=k(t)\, \mathrm{d} t. \end{equation}
In particular, $E$ charges no level set of $w$.
Let $V$ be a relatively compact coordinate domain such that $F$ has a positive essential lower bound on a neighborhood of $\overline V$. Then there is $C_ V<\infty $ such that every piecewise $C^1$ Lipschitz function $p$ on $[a,b]$ satisfies
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\begin{equation} \int _ V|\mathrm{d}(p(w))|\, \mathrm{d}\lambda \leq C_ V\left(\int _ V|p'(w)|^2\, \mathrm{d} E\right)^{1/2}, \end{equation}
where $\mathrm{d}\lambda $ is Euclidean coordinate volume.
Proof.
Locally, expand $T$ into powers of the smooth form $\omega $ multiplied by closed Bedford–Taylor products of $\mathrm{dd}^{\mathrm{c}}u$ and $\mathrm{dd}^{\mathrm{c}}v$. The operator $\mathrm{dd}^{\mathrm{c}}$ then acts only on the powers of $\omega $, and the local mass bounds in section 5.27 show that $\mathrm{dd}^{\mathrm{c}}T$ is a finite signed measure.
We first construct $E$ and prove (14.24.6). On a coordinate ball, convolve $u$, $v$ and the coefficients of $\omega $ with a common nonnegative radial mollifier. Write the resulting smooth positive forms as $A_\rho =\omega _\rho +\mathrm{dd}^{\mathrm{c}}u_\rho $ and $B_\rho =\omega _\rho +\mathrm{dd}^{\mathrm{c}}v_\rho $, and let $T_\rho $ be their mixed sum. On a slightly larger ball, add the same fixed multiple of $|z|^2$ to each potential to obtain plurisubharmonic functions. Their radial regularizations decrease to the originals, so Bedford–Taylor continuity applies to all closed Hessian products. Since $u,v$ are continuous, $u_\rho ,v_\rho ,w_\rho $ converge uniformly on compact subsets.
For a closed smooth product $S_\rho $ appearing in $T_\rho $, the identity
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\begin{equation} \mathrm{d} w_\rho \wedge \mathrm d^{\mathrm c}w_\rho \wedge S_\rho =\tfrac 12\mathrm{dd}^{\mathrm{c}}(w_\rho ^2S_\rho )-w_\rho \mathrm{dd}^{\mathrm{c}}w_\rho \wedge S_\rho \end{equation}
has a distributional limit: both Hessian products on the right converge weakly with uniformly bounded local variation, and their weights converge uniformly. The same holds after multiplication by the convergent smooth factors coming from $\omega _\rho $. Thus the positive measures $E_\rho =\mathrm{d} w_\rho \wedge \mathrm d^{\mathrm c}w_\rho \wedge T_\rho $ converge to a finite positive measure $E$. By (14.24.9), this limit does not depend on the regularization, so the local limits agree on overlapping charts.
For smooth regularizations, the chain rule gives
\[ \mathrm{dd}^{\mathrm{c}}\chi (w_\rho )\wedge T_\rho =\chi ''(w_\rho )E_\rho +\chi '(w_\rho )\mathrm{dd}^{\mathrm{c}}w_\rho \wedge T_\rho . \]
The last current tends to zero, because $\mathrm{dd}^{\mathrm{c}}w_\rho \wedge T_\rho =A_\rho ^ n-B_\rho ^ n$ tends weakly to $A^ n-B^ n=0$ with uniformly bounded variation, and $\chi '(w_\rho )$ converges uniformly. Passing to the limit and integrating by parts on the compact manifold $X$ gives (14.24.6). A partition of unity justifies this passage without a global regularization; the terms containing derivatives of the cutoff functions cancel after summation.
Let $\sigma =w_*(\mathrm{dd}^{\mathrm{c}}T)$ and $\nu =w_*E$. Equation (14.24.6) says that $\nu ''=\sigma $ as distributions on $\mathbb R$. Stokes' theorem and $\mathrm{dd}^{\mathrm{c}}w\wedge T=0$ give
\[ \sigma (\mathbb R)=\int _ X\mathrm{dd}^{\mathrm{c}}T=0,\qquad \int _{\mathbb R}s\, \mathrm{d}\sigma (s)=\int _ Xw\, \mathrm{dd}^{\mathrm{c}}T=\int _ X\mathrm{dd}^{\mathrm{c}}w\wedge T=0. \]
Consequently $k(t)=\int (s-t)_+\, \mathrm{d}\sigma (s)$ is globally Lipschitz and vanishes outside $[a,b]$. It satisfies $k''=\sigma $, so the compactly supported distribution $\nu -k(t)\, \mathrm{d} t$ has second derivative zero and therefore vanishes. Positivity of $\nu $ and continuity of $k$ imply $k\geq 0$. This proves (14.24.7), and the assertion about level sets follows because $\nu $ is absolutely continuous.
We now prove (14.24.8). On a coordinate neighborhood of $\overline V$, set $\beta =\mathrm{dd}^{\mathrm{c}}|z|^2$ and choose $c_ V>0$ with $F\omega ^ n\geq c_ V\beta ^ n$. Let $A_{\mathrm{ac}}$ denote the absolutely continuous part of the current $A$, whose coefficients are locally integrable functions. Applying lemma 5.28.10 with the constant function $g=c_ V^{1/n}$ and differentiating the coefficient measures, we obtain $\det _\beta A_{\mathrm{ac}}\geq c_ V$ almost everywhere. The local Sobolev regularity in section 5.27 gives $w_\rho \to w$ strongly in $W^{1,2}_{\mathrm{loc}}$, so a subsequence of the gradients converges almost everywhere. Moreover, $A_\rho \to A_{\mathrm{ac}}$ almost everywhere, by differentiation of the coefficient measures.
Since $T_\rho $ contains the term $A_\rho ^{n-1}$ and all its terms are positive, Fatou's lemma, applied to $E_\rho $, yields the measure inequality
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\begin{equation} E\geq \mathrm{d} w\wedge \mathrm d^{\mathrm c}w\wedge A_{\mathrm{ac}}^{n-1}. \end{equation}
The cofactor matrix of $A_{\mathrm{ac}}$ has smallest eigenvalue at least $\det A_{\mathrm{ac}}/\operatorname {tr}A_{\mathrm{ac}}\geq c_ V/\operatorname {tr}A_{\mathrm{ac}}$, where traces and determinants are taken with respect to $\beta $. The trace is locally integrable because $A$ has locally finite mass. The chain rule for Sobolev functions, (14.24.10) and the Cauchy–Schwarz inequality give
\[ \int _ V|\mathrm{d}(p(w))|\, \mathrm{d}\lambda \leq C\left(\int _ V|p'(w)|^2\, \mathrm{d} E\right)^{1/2} \left(\int _ V\frac{\operatorname {tr}A_{\mathrm{ac}}}{c_ V}\, \mathrm{d}\lambda \right)^{1/2}. \]
The last factor is finite and is absorbed into $C_ V$. The values of $p'$ at the finitely many corners of $p$ are immaterial, because $E$ charges no level set of $w$.
$\square$
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