Proposition 16.6.11.363E28FF4A61 Let $\varphi \in \mathrm{PSH}(X,\theta )$. Then
In particular,
and the upper semicontinuous regularization in (16.6.8) is not necessary.
363E28FF4A61Proposition 16.6.11.363E28FF4A61 Let $\varphi \in \mathrm{PSH}(X,\theta )$. Then
In particular,
and the upper semicontinuous regularization in (16.6.8) is not necessary.
Proof. In view of proposition 16.6.2, it suffices to show that for $k \in \mathbb {Z}_{>0}$, we have
5888DEC3C930
16.6.12
By proposition 5.14.3, we can find $\psi _ i\in \mathrm{PSH}(X,\theta )$ ($i\in \mathbb {Z}_{>0}$) such that $\psi _ i\leq 0$, $\psi _ i\sim _{\mathcal{I}}\varphi $ for all $i\geq 1$ and
By proposition 16.6.5, we may replace $\psi _ i$ by $\psi _1\lor \cdots \lor \psi _ i$ and assume that the sequence $\psi _ i$ is increasing. In this case, it follows from the strong openness theorem theorem 5.16.21 that for each $k\in \mathbb {Z}_{>0}$, we have
for $j$ large enough. $\square$
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