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Proposition 14.2.4366AA2E61158

Proposition 14.2.4.366AA2E61158 Suppose $(u,b)$ and $(v,c)$ are smooth solutions of (14.1.1) with the same $F$ and $\mathrm{d}V$. Then $b=c$ and $u-v$ is constant.

Proof. At a maximum of $u-v$, one has $\omega _ u\leq \omega _ v$, so the equations give $\mathrm{e}^ b\leq \mathrm{e}^ c$. At a minimum one obtains $\mathrm{e}^ b\geq \mathrm{e}^ c$. Therefore $b=c$.

Put $h=u-v$ and $\eta _ t=\omega _ v+t\mathrm{dd}^{\mathrm{c}}h=(1-t)\omega _ v+t\omega _ u$ for $0\leq t\leq 1$. These forms are strictly positive. Subtracting the logarithms of the two equations and writing the difference as the integral of its derivative along the segment, we obtain

\[ 0=\int _0^1 n\, \frac{\mathrm{dd}^{\mathrm{c}}h\wedge \eta _ t^{n-1}}{\eta _ t^ n}\, \mathrm{d}t. \]

The right-hand side is a linear second-order operator applied to $h$. Its coefficients are smooth, its principal part is uniformly elliptic on the compact manifold, and it has no zeroth-order term. The strong maximum principle therefore implies that $h$ is constant. $\square$

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