For $q\in \operatorname {int}P$ and $\tau \in (S^1)^ n$, let $\Psi (q,\tau )=\mathrm e^{r(q)/2}\tau $ be the point of $T$ with coordinates $\mathrm e^{r_ j(q)/2}\tau _ j$. Thus $\Psi (q,\cdot )$ parametrizes the real torus $\{ r=r(q)\} $, and we call the image of $Q\times (S^1)^ n$ the moment shell of $Q$. Here and below, $\langle S^ k\rangle $ denotes the non-pluripolar product of a closed positive $(1,1)$-current $S$; in top degree it is the non-pluripolar Monge–Ampère measure of theorem 13.14.3.
Theorem 18.45.11.C6669A63F760 Against every continuous test function on $X$,
BAC3E7E057E7
18.45.12
\begin{equation} \frac{d!}{m^ d}B_ m\nu \rightharpoonup \mu _ Q=\Psi _*(d!\, \mathrm dq_\Lambda \, \mathrm d\tau ), \qquad \Psi (q,\tau )=\mathrm e^{r(q)/2}\tau . \end{equation}
The mass of $\mu _ Q$ is $d!\operatorname {vol}_\Lambda (Q)>0$. If $d=0$, then $\mu _ Q$ is the Haar probability measure on one real $n$-torus. If $d<n$, then $\mu _ Q$ is singular with respect to smooth volume forms on $X$, and
\[ \left\langle (\theta +\mathrm{dd}^{\mathrm{c}}E_ Q)^{d+1}\right\rangle =0. \]
If $d=n$, then $\mu _ Q=\langle (\theta +\mathrm{dd}^{\mathrm{c}}E_ Q)^ n\rangle $.
Proof.
For $\alpha \in mQ\cap \mathbb Z^ n$ and $q=\alpha /m$, the normalized monomial $z^\alpha e^ m$ gives the probability measure $\mathrm dP_{m,q}=A_ m(\alpha )^{-1} \mathrm e^{m(q\cdot r-F(r))}a(r)\, \mathrm dr\, \mathrm d\tau $ on $T$. For every $\eta >0$ there is $c_\eta >0$ such that $F(r)-q\cdot r+F^*(q)\geq c_\eta $ whenever $|r-r(q)|\geq \eta $, uniformly for $q\in Q$: on a large compact set this follows from the uniqueness of the minima, and outside it from (18.45.5), which is uniform on $Q$. Together with (18.45.9), this gives $P_{m,q}\{ |r-r(q)|\geq \eta \} \leq C m^{n/2}\mathrm e^{-mc_\eta }$. Hence, for every continuous function on $X$, its integral against $P_{m,q}$ differs from its average over the torus $\{ r=r(q)\} $ by $o(1)$, uniformly in $q\in Q$. The identity $d!m^{-d}B_ m\nu =d!m^{-d}\sum _\alpha P_{m,\alpha /m}$ and the lattice Riemann sums prove (18.45.12). When $d<n$, the measure $\mu _ Q$ is carried by the moment shell, which has real dimension $n+d<2n$, so it is singular with respect to smooth volume forms.
For the curvature, note that $\theta +\mathrm{dd}^{\mathrm{c}}E_ Q=\mathrm{dd}^{\mathrm{c}}G_ Q$ on $T$. By uniform strong convexity of $F^*$ on $Q$, the slope $q(r)$ maximizing $q\cdot r-F^*(q)$ over $Q$ is unique. Adding the variational inequalities at $r$ and $s$ gives $(r-s)\cdot (q(r)-q(s))\geq c|q(r)-q(s)|^2$. Thus $q$ is Lipschitz, and comparison of the maximal values gives $\nabla G_ Q=q$. Hence $G_ Q$ is $C^{1,1}$, and its Hessian has rank at most $d$ almost everywhere, since $q(r)\in b+W$. In logarithmic coordinates, convex mollifications of $G_ Q$ converge in $C^1$, their Hessians stay bounded and converge in $L^ p_{\mathrm{loc}}$ for every finite $p$, and their minors converge in $L^1_{\mathrm{loc}}$. Induction on the degree in the Bedford–Taylor definition of products of bounded plurisubharmonic functions, together with integration by parts, identifies the powers of $\mathrm{dd}^{\mathrm{c}}G_ Q$ on $T$ with the measures given by these minors. The non-pluripolar product agrees with them on $T$ and puts no mass on the pluripolar set $X\setminus T$. The bound on the rank therefore proves the vanishing assertion.
When $d=n$, a maximizer in the interior of $Q$ satisfies $r=\nabla F^*(q)$, so $G_ Q=F$ on the set where $\nabla F(r)\in \operatorname {int}Q$. Elsewhere the maximizing slope lies in one of the finitely many facets of $Q$. On the set where it lies in a given facet, its component normal to that facet is constant, so the derivative of this component vanishes at almost every point of the set: at a point of differentiability and of density, a nonzero derivative would force a cone of positive density outside the set. Consequently $\det D^2G_ Q=\boldsymbol 1_{\{ \nabla F(r)\in Q\} }\det D^2F$ almost everywhere. In our normalization, $(\mathrm{dd}^{\mathrm{c}}F)^ n=n!\det D^2F(r)\, \mathrm dr\, \mathrm d\tau $. The change of variables $q=\nabla F(r)$ gives the asserted identity for the top product.
$\square$
For any Hermitian form $\omega $ on $X$, closed or not, the map $\Psi $ embeds $\operatorname {relint}Q\times (S^1)^ n$ onto a real $(n+d)$-dimensional submanifold $S_ Q=\Psi (\operatorname {relint}Q\times (S^1)^ n)$; for $d=0$ this is a single torus. Let $g_\omega (u,v)=\omega (u,Jv)$ be the associated Riemannian metric, and define the function $\mathcal J_\omega >0$ by $\Psi ^*\mathrm d\operatorname {vol}_{\omega ,S_ Q} =\mathcal J_\omega \, \mathrm dq_\Lambda \, \mathrm d\tau $, where $\mathrm d\operatorname {vol}_{\omega ,S_ Q}$ is the Riemannian volume of $S_ Q$ for $g_\omega $. Since the relative boundary has measure zero,
\[ \mathrm d\mu _ Q=\frac{d!}{\mathcal J_\omega \circ \Psi ^{-1}} \, \mathrm d\operatorname {vol}_{\omega ,S_ Q}. \]
If $d<n$, the mixed measure $\langle (\theta +\mathrm{dd}^{\mathrm{c}}E_ Q)^ d\rangle \wedge \omega ^{n-d}$, where the zeroth power is interpreted as $1$ when $d=0$, has a locally bounded density on $T$ and gives $S_ Q$ zero mass. Hence it differs from $\mu _ Q$. The limit $\mu _ Q$ does not depend on the invariant probability measure $\nu $, although the norms in each degree do.
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