Pome

Theorem 17.13.21B28F0A28CB3E

Theorem 17.13.21.B28F0A28CB3E The Legendre transform in definition 17.13.1 is a bijection

6D5BA4827FF5 17.13.22
\begin{equation} \mathrm{TC}(X,\theta ;\phi )\xrightarrow {\sim } \mathcal{R}(X,\theta ;\phi ). \end{equation}

Moreover, this bijection restricts to the following bijections:

AE510D6D0C2F 17.13.23
\begin{equation} \mathrm{TC}^1(X,\theta ;\phi )\xrightarrow {\sim } \mathcal{R}^1(X,\theta ;\phi ),\quad \mathrm{TC}^{\infty }(X,\theta ;\phi )\xrightarrow {\sim } \mathcal{R}^{\infty }(X,\theta ;\phi ). \end{equation}

For any $\Gamma \in \mathrm{TC}^1(X,\theta ;\phi )$, we have

4884EC5C8FA9 17.13.24
\begin{equation} \mathbf{E}^{\phi }(\Gamma )=\mathbf{E}^{\phi }(\Gamma ^*). \end{equation}

Proof. Step 1. We first establish (17.13.22).

It follows from 17.13.11 that the forward map is well-defined. The inverse map is given by (17.13.14). We show that the inverse map is also well-defined. Given $\ell \in \mathcal{R}(X,\theta ;\phi )$, we know from 17.13.15 that $\ell ^*\in \mathrm{TC}(X,\theta ;\phi )$. We need to show that $\ell ^*\in \mathrm{TC}(X,\theta ;\phi )$.

The equality $\ell ^*_{-\infty }=\phi $ was proved in 17.13.15. Therefore, $\ell ^*\in \mathrm{TC}(X,\theta ;\phi )$ as expected.

The two operations are inverse to each other thanks to corollary 21.11.26. Hence, (17.13.22) is established.

Step 2. Next we consider the bounded situation. Namely, we want to establish the second half of (17.13.23).

Suppose that $\Gamma \in \mathrm{TC}^{\infty }(X,\theta ;\phi )$. Take $\tau _0\in \mathbb {R}$ so that $\Gamma _{\tau }=\phi $ for all $\tau \leq \tau _0$. It follows from (17.13.2) that

\[ \Gamma _ t^*\geq \phi +t\tau _0 \]

for all $t>0$. Therefore, $\Gamma ^*_ t\sim \phi $ for all $t>0$ and hence $\Gamma ^*\in \mathcal{R}^{\infty }(X,\theta ;\phi )$.

Conversely, suppose that $\ell \in \mathcal{R}^{\infty }(X,\theta ;\phi )$. Thanks to proposition 17.10.37, there is a constant $C>0$ such that

\[ \ell _ t\geq \phi -Ct. \]

Therefore, according to (17.13.14), we have

\[ \ell ^*_{\tau }\geq \inf _{t>0} \Bigl ( \phi -(C+\tau )t \Bigr )=\phi \]

if $\tau \leq -C$. Therefore, $\ell ^*_{\tau }=\phi $ for all $\tau \leq -C$.

Step 3. We establish (17.13.24) and the first half of (17.13.23).

Step 3.1. We reduce to the case where $\Gamma _{\max }=0$.

Suppose that we define

\[ \Gamma '_{\tau }=\Gamma _{\tau +\Gamma _{\max }},\quad \forall \tau <0. \]

Then $\Gamma '\in \mathrm{TC}(X,\theta ;\phi )$ as well and for all $t>0$,

\[ \Gamma '^*_ t=\sup _{\tau <0} \left( t\tau +\Gamma '_{\tau } \right)=\sup _{\tau <\Gamma _{\max }} \left( t\tau +\Gamma _{\tau } \right)-t\Gamma _{\max }=\Gamma ^*_ t-t\Gamma _{\max }. \]

Therefore,

\[ \mathbf{E}^{\phi }\left(\Gamma '^*\right)=\mathbf{E}^{\phi }\left(\Gamma ^*\right)-\Gamma _{\max }\int _ X \theta _{\phi }^ n. \]

by (16.5.13). Using (17.12.12), we also have

\[ \begin{aligned} \mathbf{E}^{\phi }(\Gamma ')=& \int _{-\infty }^0 \left( \int _ X \theta _{\Gamma '_{\tau }}^ n-\int _ X \theta _{\phi }^ n \right)\, \mathrm{d}\tau \\ =& \int _{-\infty }^{\Gamma _{\max }}\left( \int _ X \theta _{\Gamma _{\tau }}^ n-\int _ X \theta _{\phi }^ n \right)\, \mathrm{d}\tau \\ =& \mathbf{E}^{\phi }(\Gamma )-\Gamma _{\max }\int _ X \theta _{\phi }^ n. \end{aligned} \]

Therefore, it suffices to establish (17.13.24) for $\Gamma '$ in place of $\Gamma $.

Step 3.2. We assume that $\Gamma _{\max }=0$ and $\Gamma \in \mathrm{TC}^{\infty }(X,\theta ;\phi )$. We prove (17.13.24).

For $N\in \mathbb {Z}_{>0}$, $M \in \mathbb {Z}$, we introduce the following:

\[ \Gamma ^{*,N,M}_ t \coloneqq \max _{\substack {k \in \mathbb {Z} \\ k \leq M}} \left(\Gamma _{k/2^ N} + tk/2^ N\right)\in \mathcal{E}^{\infty }(X,\theta ;\phi ),\quad t>0. \]

We first claim that for all $t>0$, $N\in \mathbb {Z}_{>0}$ and $M\in \mathbb {Z}_{<0}$,

1C55A624E61E 17.13.25
\begin{equation} \frac{t}{2^ N} \int _ X \theta ^ n_{\Gamma _{(M+1)/2^ N}}\leq E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,M+1}\right)-E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,M}\right)\leq \frac{t}{2^ N} \int _ X \theta ^ n_{\Gamma _{M/2^ N}}. \end{equation}

Assuming this, let us prove (17.13.24).

Fixing $N$, let $M=\lfloor 2^{N}\Gamma _{\min }\rfloor $. Recall that $\Gamma _{\min }$ is defined in (17.12.11). Then repeated applications of (17.13.25) yield

\[ \sum _{j=M+1}^0 \frac{t}{2^ N} \int _ X \theta ^ n_{\Gamma _{j/2^ N}}\leq E^{\phi }_{\theta }\left(\Gamma _ t^{*,N,0}\right)-E^{\phi }_{\theta }\left(\Gamma _ t^{*,N,M}\right)\leq \sum _{j=M}^{-1} \frac{t}{2^ N} \int _ X \theta ^ n_{\Gamma _{j/2^ N}}. \]

Since $M \leq 2^{N}\Gamma _{\min }$, we have

\[ \Gamma ^{*,N,M}_ t =\phi +t M/2^ N. \]

Using (16.5.13), we can continue to write

\[ \sum _{j=M+1}^0 \frac{t}{2^ N} \left(\int _ X \theta ^ n_{\Gamma _{j/2^ N}} - \int _ X \theta ^ n_{\phi }\right)\leq E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,0}\right)\leq \sum _{j=M}^{-1} \frac{t}{2^ N} \left(\int _ X \theta ^ n_{\Gamma _{j/2^ N}} - \int _ X \theta ^ n_{\phi }\right). \]

We now notice that we have Riemann sums on both the left and right of the above inequality. Moreover, as $N\to \infty $, the potentials $\Gamma _ t^{*,N,0}$ increase to $\Gamma _ t^*$, hence their energies converge to $E^\phi _\theta (\Gamma _ t^*)$ by proposition 16.5.37. Using proposition 17.12.9, it is possible to let $N \to \infty $ and obtain

85E0D04C585D 17.13.26
\begin{equation} E_{\theta }^{\phi }(\Gamma _ t^{*})=t\mathbf{E}^{\phi }(\Gamma ) \end{equation}

So (17.13.24) follows as desired.

It remains to argue (17.13.25). Fix $t>0$, $N\in \mathbb {Z}_{>0}$ and $M\in \mathbb {Z}$. By proposition 16.5.36,

877135CB19C2 17.13.27
\begin{equation} \begin{aligned} \int _ X \left(\Gamma _ t^{*,N,M+1}-\Gamma _ t^{*,N,M}\right)\, \theta ^ n_{\Gamma _ t^{*,N,M+1}}\leq & E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,M+1}\right)-E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,M}\right)\\ \leq & \int _ X \left(\Gamma _ t^{*,N,M+1}-\Gamma _ t^{*,N,M}\right)\, \theta ^ n_{\Gamma _ t^{*,N,M}}. \end{aligned} \end{equation}

Clearly $\Gamma _ t^{*,N,M+1} \geq \Gamma _ t^{*,N,M}$. Moreover, since $\mathbb {R}\ni \tau \mapsto \Gamma _{\tau }+t\tau $ is concave, we notice that

\[ U_ t \coloneqq \left\{ \Gamma ^{*,N,M+1}_ t>\Gamma ^{*,N,M}_ t\right\} = \left\{ \Gamma _{(M+1)/2^ N} + 2^{-N}t >\Gamma _{M/2^ N}\right\} , \]

and on $U_ t$ we have

23E6778F003A 17.13.28
\begin{equation} \Gamma _ t^{*,N,M+1} = \Gamma _{(M+1)/2^ N} + t (M+1)/2^{N},\quad \Gamma _ t^{*,N,M} = \Gamma _{M/2^ N} + t M /2^{N}. \end{equation}

We also note that $U_ t$ is $\mathcal{F}$-open by corollary 5.15.19. So from the lower bound in (17.13.27), we have

\[ \begin{aligned} E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,M+1}\right)-E_{\theta }^{\phi }\left(\Gamma _ t^{*,N,M}\right)\geq & \int _{U_ t} \left(\Gamma _ t^{*,N,M+1}-\Gamma _ t^{*,N,M}\right)\, \theta ^ n_{\Gamma _ t^{*,N,M+1}}\\ = & \int _{U_ t} \left(\Gamma _{(M+1)/2^ N}-\Gamma _{M/2^ N}+t2^{-N}\right)\, \theta ^ n_{\Gamma _{(M+1)/2^ N}}\\ \geq & \int _{\left\{ \Gamma _{(M+1)/2^ N}=0\right\} }t2^{-N}\, \theta ^ n_{\Gamma _{(M+1)/2^ N}}, \end{aligned} \]

where on the second line, we applied (17.13.28) and proposition 13.11.4, on the third line, we applied the fact that $\theta _{\Gamma _{(M+1)/2^ N}}^ n$ is supported on the set (cf. theorem 16.3.12)

\[ \left\{ \Gamma _{(M+1)/2^ N}=0\right\} \subseteq U_ t\cap \left\{ \Gamma _{M/2^ N}=0\right\} . \]

When $(M+1)/2^ N=0$, we use proposition 16.4.3 to see that $P_\theta [\Gamma _0]=\Gamma _0$, since $\Gamma _0$ is the decreasing limit of the model potentials $\Gamma _\tau $ as $\tau \nearrow 0$. Thus theorem 16.3.12 applies to this endpoint as well.

We have deduced the first inequality in (17.13.25). Next, we apply the upper bound part in (17.13.27) and compute similarly

\[ \begin{aligned} E_{\theta }^{\phi }(\Gamma _ t^{*,N,M+1})-E_{\theta }^{\phi }(\Gamma _ t^{*,N,M})\leq & \int _ X \left(\Gamma _ t^{*,N,M+1}-\Gamma _ t^{*,N,M}\right)\, \theta ^ n_{\Gamma _ t^{*,N,M}}\\ =& \int _{U_ t} \left(\Gamma _{(M+1)/2^ N}-\Gamma _{M/2^ N}+t2^{-N}\right)\, \theta ^ n_{\Gamma _{M/2^ N}}\\ \leq & \int _{\{ \Gamma _{M/2^ N}=0\} \cap U_ t}\left(\Gamma _{(M+1)/2^ N}+t2^{-N}\right)\, \theta ^ n_{\Gamma _{M/2^ N}} \\ \leq & \int _{\{ \Gamma _{M/2^ N}=0\} \cap U_ t} t2^{-N}\, \theta ^ n_{\Gamma _{M/2^ N}}. \end{aligned} \]

We conclude the latter half of (17.13.25).

Step 3.3. We assume that $\Gamma _{\max }=0$. Now $\Gamma \in \mathrm{TC}(X,\theta ;\phi )$ only.

For each $\epsilon >0$, we introduce $\Gamma ^{\epsilon }\in \mathrm{TC}^{\infty }(X,\theta ;\phi )$ as follows:

  1. 1E08B0569766

    Let $\Gamma ^{\epsilon }_{\max }=0$, and

  2. 70863808F7A7

    we set

    \[ \Gamma ^{\epsilon }_{\tau }= \begin{cases} \phi ,& \textup{if }\tau \leq -\epsilon ^{-1};\\ P_{\theta }\left[ (1+\epsilon \tau )\Gamma _{\tau }-\epsilon \tau \phi \right],& \textup{if }\tau \in \left(-\epsilon ^{-1},0\right). \end{cases} \]

The concavity and monotonicity in $\tau $ follow from proposition 16.4.2. The value at $-\infty $ is $\phi $. Moreover, $\Gamma ^\epsilon _\tau =\phi $ for $\tau \leq -\epsilon ^{-1}$, so $\Gamma ^\epsilon \in \mathrm{TC}^\infty (X,\theta ;\phi )$.

It follows from corollary 16.9.38 and corollary 16.9.14 that for each $\tau <0$, the potentials $\Gamma ^{\epsilon }_{\tau }$ decrease to $\Gamma _{\tau }$ as $\epsilon \searrow 0$. Applying proposition 16.4.4, we have

\[ \lim _{\epsilon \to 0+} \int _ X \left(\theta +\mathrm{dd}^{\mathrm{c}}\Gamma ^{\epsilon }_{\tau }\right)^ n=\int _ X \left(\theta +\mathrm{dd}^{\mathrm{c}}\Gamma _{\tau }\right)^ n \]

for all $\tau <0$. Hence, by the monotone convergence theorem and Step 3.2, we find

DBCF50A40C12 17.13.29
\begin{equation} \mathbf{E}^{\phi }(\Gamma )=\lim _{\epsilon \to 0+}\mathbf{E}^{\phi }(\Gamma ^{\epsilon })=\lim _{\epsilon \to 0+}\mathbf{E}^{\phi }(\Gamma ^{\epsilon *})=\lim _{\epsilon \to 0+} E_{\theta }^{\phi }(\Gamma ^{\epsilon *}_1), \end{equation}

where the last equality follows from (17.13.26). Furthermore, according to proposition 21.11.36, we have

\[ \Gamma ^*_ t=\inf _{\epsilon >0} \Gamma ^{\epsilon *}_ t \]

for all $t>0$. Note that we do not have to take the closure of the right-hand side since it is automatically upper semicontinuous in $t$.

Now suppose that $\Gamma \in \mathrm{TC}^1(X,\theta ;\phi )$. Then by (17.13.29), as $\epsilon \to 0+$, $(\Gamma _ t^{\epsilon *})_{\epsilon }$ is a decreasing Cauchy net in $\mathcal{E}^1(X,\theta ;\phi )$ and hence by theorem 17.10.63 for each $t>0$,

\[ E_{\theta }^{\phi }\left(\Gamma ^*_ t\right)=\lim _{\epsilon \to 0+}E_{\theta }^{\phi }\left(\Gamma ^{\epsilon ,*}_ t\right)=t\mathbf{E}^{\phi }(\Gamma )>-\infty , \]

where we have applied (17.13.26) and (17.13.29). Hence, $\Gamma ^*\in \mathcal{R}^1(X,\theta ;\phi )$. Moreover, (17.13.24) follows.

Conversely, suppose that $\Gamma ^*\in \mathcal{R}^1(X,\theta ;\phi )$. Then (17.13.29) implies that

\[ \mathbf{E}^{\phi }(\Gamma )=\lim _{\epsilon \to 0+} E_{\theta }^{\phi }\left(\Gamma ^{\epsilon *}_1\right) \geq E_{\theta }^{\phi }\left(\Gamma ^*_1\right)>-\infty . \]

Hence, $\Gamma \in \mathrm{TC}^1(X,\theta ;\phi )$. $\square$

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