Theorem 18.7.6.EA60F3EAF248 For every $u\in \mathrm{PSH}(X,\theta )$ and every choice in (18.7.5), put
\[ q_ j=P_{\theta +\epsilon _ jh}[a_ j]. \]
Then $q_ j$ has analytic singularities, and
\[ q_ j=P_{\theta +\epsilon _ jh}[a_ j]_{\mathcal I} \searrow P_\theta [u]_{\mathcal I} \]
pointwise and in $L^1$. The limit is independent of the choice of the approximants $a_ j$, of the error bounds $\epsilon _ j$ and of the metric $h$.
Proof.
By proposition 18.4.8, $q_ j=P_{\theta +\epsilon _ jh}[a_ j]_{\mathcal I}\sim a_ j$. Since the backgrounds decrease and $a_{j+1}\preceq a_ j$, the function $q_{j+1}$ is a competitor for $P_{\theta +\epsilon _ jh}[a_ j]$. Hence $q_{j+1}\leq q_ j$.
The inequality $a_ j\geq u$ gives $u\preceq _{\mathcal I}a_ j$. For every local divisor $E$, lemma 5.38.9 gives
\[ \nu _ E(a_ j)=\frac1{m_ j}\operatorname {ord}_ E\mathcal I(m_ ju) \longrightarrow \nu _ E(u). \]
By proposition 18.7.1, $q_ j\to p:=P_\theta [u]_{\mathcal I}$ in $L^1$, and $p\leq q_ j\leq 0$. The decreasing limit of the $q_ j$ is therefore bounded below by $p$; it is a $\theta $-plurisubharmonic function that agrees with $p$ almost everywhere, hence everywhere. This identifies the limit in terms of $\theta $ and the multiplier-ideal class of $u$ alone, which proves the asserted independence.
$\square$
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