E6AC80354EB9
On a curve the preceding theory becomes explicit. The part of the curvature current carried by the pole set determines the ordinary envelope, and its atomic part determines the ideal envelope. Comparing these two measures describes both the zero-volume boundary and the failure of analytic approximation for diffuse polar singularities. Total variation of the polar measures keeps this singularity data and at the same time controls convergence of the model potentials in capacity.
In this section, $Y$ is a compact connected Riemann surface, $\theta $ is a smooth positive $(1,1)$-form on $Y$, and $A=\int _ Y\theta $. By Stokes' theorem every bounded $\theta $-plurisubharmonic function has mass $A$; thus $Y$ has the bounded mass property, $\theta $ is big, and the preceding results apply with $Y$ in place of $X$. For $u\in \mathrm{PSH}(Y,\theta )$ write $T_ u=\theta +\mathrm{dd}^{\mathrm{c}}u$, and let $\mu _ u=\mathbf1_{\{ u=-\infty \} }T_ u=T_ u^{\mathrm{pol}}$ be the polar curvature of $u$ (subsection 5.27.13); in this and the following sections, $\mu _ u$ no longer denotes $\mathrm{MA}_\theta (u)$. A positive measure carried by a polar set will be called a polar measure. Since $\theta $ is closed, the two singularity volumes of $u$ coincide with
\[ U(u)=\int _ Y\mathrm{MA}_\theta (u)=A-\mu _ u(Y). \]
Fix a nonpositive Green kernel $G$ for $\eta =\theta /A$, as in subsection 20.3.9, so that $\mathrm{dd}^{\mathrm{c}}_ xG(x,y)=\delta _ y-\eta $, where $\delta _ y$ is the Dirac measure at $y$. We write $\| \cdot \| _{\mathrm{TV}}$ for the total variation norm of finite signed measures.
Lemma 13.28.1.2422DD1AB3AB For a polar measure $\mu $ on $Y$ with $\mu (Y)\leq A$, put
\[ w_\mu (x)=\int _ YG(x,y)\, \mathrm{d}\mu (y),\qquad p_\mu =P_\theta [w_\mu ]. \]
Then $p_\mu \sim w_\mu $, $\mu _{p_\mu }=\mu $ and $U(p_\mu )=A-\mu (Y)$. Every $u\in \mathrm{PSH}(Y,\theta )$ satisfies
B922F9AF307B
13.28.2
\begin{equation} P_\theta [u]=p_{\mu _ u}. \end{equation}
Consequently $\mu \mapsto p_\mu $ is a bijection from the polar measures of mass at most $A$ onto the set of all ordinary models on $Y$.
Proof.
The bounds for the Green kernel give $w_\mu \in L^1(Y)$ and
\[ T_{w_\mu }=\mu +(A-\mu (Y))\eta . \]
In particular $w_\mu $ is $\theta $-plurisubharmonic, and its polar curvature is $\mu $. We claim that, for every $v\in \mathrm{PSH}(Y,\theta )$,
C63C9A28E474
13.28.3
\begin{equation} v\preceq w_\mu \quad \Longleftrightarrow \quad T_ v\geq \mu . \end{equation}
The forward implication follows from corollary 5.27.15, which gives $T_ v\geq \mu _ v\geq \mu _{w_\mu }=\mu $. Conversely, if $T_ v\geq \mu $, the distribution $v-w_\mu $ satisfies $\mathrm{dd}^{\mathrm{c}}(v-w_\mu )\geq -(A-\mu (Y))\eta $, so its quasi-subharmonic representative is bounded above on the compact curve $Y$. By lemma 5.24.3, $v\preceq w_\mu $.
Thus $p_\mu $ is the upper envelope of all $v\leq 0$ with $T_ v\geq \mu $. This family is closed under maxima by (5.27.16). By Choquet's lemma the envelope is the limit of an increasing sequence of such maxima, which converges in $L^1$; hence the current inequality $T_{p_\mu }\geq \mu $ passes to the limit. Also $p_\mu \geq w_\mu -\sup _ Yw_\mu $. Hence $b=p_\mu -w_\mu $ has a quasi-subharmonic representative that is bounded below, and compactness bounds it above. Therefore $p_\mu \sim w_\mu $. The positive measure
\[ T_{p_\mu }-\mu =(A-\mu (Y))\eta +\mathrm{dd}^{\mathrm{c}}b \]
charges no polar set because $b$ is bounded. This proves $\mu _{p_\mu }=\mu $ and $U(p_\mu )=A-\mu (Y)$, and ordinary equivalence gives $P_\theta [p_\mu ]=P_\theta [w_\mu ]=p_\mu $.
For arbitrary $u$, take $\mu =\mu _ u$. Then $T_ u\geq \mu $, so (13.28.3) gives $u\preceq p_\mu $, and $U(u)=A-\mu (Y)=U(p_\mu )$. If this mass is positive, corollary 13.19.8 gives (13.28.2). If it is zero, then $\mu (Y)=A$ and $T_ u=\mu =T_{w_\mu }$. The difference $u-w_\mu $ is then harmonic on $Y$ and hence constant, which gives the same conclusion. Finally, every ordinary model $p$ equals $P_\theta [p]=p_{\mu _ p}$, and distinct polar measures give distinct models because $\mu _{p_\mu }=\mu $.
$\square$
Theorem 13.28.4.74646DD62F50 For every $u,v\in \mathrm{PSH}(Y,\theta )$,
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13.28.5
\begin{equation} d_\theta (u,v)=\| \mu _ u-\mu _ v\| _{\mathrm{TV}}. \end{equation}
In particular, $d_\theta $ is a metric on the set of ordinary models on $Y$. For positive atomic measures $D,E$ of mass at most $A$, let $q_ D,q_ E$ be the ideal models of lemma 20.3.20, with polar curvatures $D$ and $E$. Then
E72F3C33D0D0
13.28.6
\begin{equation} d_\theta (q_ D,q_ E)=\| D-E\| _{\mathrm{TV}}. \end{equation}
Proof.
By (5.27.16), the polar curvature of $\max (u,v)$ is the minimum $\mu _ u\wedge \mu _ v$ of the two measures. The formula $U=A-\mu (Y)$ therefore gives
\[ \begin{split} d_\theta (u,v)& =2U(\max (u,v))-U(u)-U(v)\\ & =\mu _ u(Y)+\mu _ v(Y)-2(\mu _ u\wedge \mu _ v)(Y)\\ & =\| \mu _ u-\mu _ v\| _{\mathrm{TV}}. \end{split} \]
The classification in lemma 13.28.1 shows that $d_\theta $ separates ordinary models, and the triangle inequality follows from that of the total variation norm. By lemma 20.3.20, the ideal models are exactly the models whose polar measures are atomic, which gives (13.28.6).
$\square$
Corollary 13.28.7.FB89848D2500 The ordinary models on $Y$ form a complete geodesic metric space for $d_\theta $. The ideal models form a closed geodesically convex subspace, which is the metric completion of the analytic ordinary models of positive mass.
Proof.
By lemma 13.28.1, theorem 13.28.4, the space of ordinary models is isometric to the set of polar measures of mass at most $A$ with the total variation norm. This set is closed in total variation: a limit is positive, satisfies the mass bound, and is carried by the countable union of polar carriers of the sequence. Completeness therefore follows from that of finite signed measures. For two such measures $\mu ,\nu $, the measures $\mu _ t=(1-t)\mu +t\nu $, $0\leq t\leq 1$, remain in this set and satisfy
\[ \| \mu _ t-\mu _ s\| _{\mathrm{TV}}=|t-s|\, \| \mu -\nu \| _{\mathrm{TV}}. \]
Their models give a constant-speed geodesic.
The atomic measures form a closed convex subset, since a total-variation limit is carried by the countable union of the sets of atoms of the sequence. Restricting to finitely many atoms and approximating the coefficients from below by rational numbers, with an arbitrarily small further decrease if needed, approximates every such measure by finite atomic measures with rational coefficients and mass strictly less than $A$. Their models have analytic singularities by lemma 20.3.20, and (13.28.6) gives the density.
$\square$
The models of positive mass do not form a complete space for $d_\theta $: for a fixed $x\in Y$, the models of $tA\delta _ x$ form a Cauchy family as $t\uparrow 1$, with a limit of zero mass. For the complete metric of theorem 13.27.4, this family is not Cauchy, because its reciprocal lower volumes diverge. The two metrics induce the same topology on models of positive mass but have different Cauchy sequences near the boundary.
The metric $d_\theta $ also controls convergence of the potentials at the zero-mass boundary. There the polar part exhausts the limiting curvature current, so its total variation controls the whole current.
Theorem 13.28.8.3F90EA1D636A Let $p_ j,p$ be ordinary models on $Y$. If $d_\theta (p_ j,p)\to 0$, then $p_ j\to p$ in $L^1$ and in capacity. If $U(p)=0$, then in addition
E5C7D16CF970
13.28.9
\begin{equation} \| T_{p_ j}-T_ p\| _{\mathrm{TV}}\leq 2d_\theta (p_ j,p)\longrightarrow 0. \end{equation}
Proof.
Write $\mu _ j=\mu _{p_ j}$ and $\mu =\mu _ p$. By (13.28.5), $\mu _ j\to \mu $ in total variation. Thus $U(p_ j)=A-\mu _ j(Y)\to U(p)$. If $U(p)>0$, the models lie in a common $\mathcal M_\delta (\theta )$ for all large $j$, and proposition 13.22.4, theorem 13.23.3 apply.
Suppose that $U(p)=0$. Then $T_ p=\mu $ and $\mu (Y)=A$, while $T_{p_ j}-\mu _ j$ is a positive measure of mass $A-\mu _ j(Y)=\mu (Y)-\mu _ j(Y)$. Consequently
\[ \| T_{p_ j}-T_ p\| _{\mathrm{TV}} \leq \| \mu _ j-\mu \| _{\mathrm{TV}}+A-\mu _ j(Y) \leq 2\| \mu _ j-\mu \| _{\mathrm{TV}}, \]
which proves (13.28.9). By normalized compactness, each subsequence has a further subsequence converging in $L^1$ to a function $q$ with supremum zero. Then $T_{p_ j}\to T_ q$ weakly, so $T_ q=T_ p$ and $\mathrm{dd}^{\mathrm{c}}(q-p)=0$. Hence $q-p$ is constant, and the normalization gives $q=p$. This proves $L^1$ convergence of the whole sequence. Finally, apply lemma 5.27.11 on finitely many nested coordinate disks: both terms on its right-hand side tend to zero, and the comparison between local and global capacities in section 5.29 gives convergence in capacity.
$\square$
For potentials with supremum zero, weak convergence $T_{p_ j}\rightharpoonup T_ p$ is equivalent to $p_ j\to p$ in $L^1$, by theorem 11.31.2 and normalized compactness. It need not imply convergence in capacity, even when the sequence and the limit are ideal models. Indeed, scaling the area-one construction in theorem 18.6.4 gives zero-mass ideal models converging to zero in $L^1$. Convergence in capacity would contradict theorem 13.15.9, since their damped measures vanish while the limiting measure is $\theta $.
Conversely, convergence in capacity does not imply convergence of the polar parts in total variation. Moving a single pole gives an example, even within the zero-mass boundary.
Example 13.28.10.98D940133E3B On $\mathbb P^1$ with the Fubini–Study form $\theta $ of area one, there are zero-mass ideal models $p_ j,p$ with $p_ j\to p$ in capacity but $d_\theta (p_ j,p)=2$ for every $j$.
Proof.
In the affine coordinate $z$, where $\theta =\mathrm{dd}^{\mathrm{c}}\log (1+|z|^2)$, put for $a\in \mathbb C$
\[ p_ a(z)=\log \frac{|z-a|^2}{(1+|z|^2)(1+|a|^2)}. \]
This function extends to $\mathbb P^1$, has supremum zero by the Cauchy–Schwarz inequality, and satisfies $T_{p_ a}=\delta _ a$. Hence it is the ideal model with polar measure $\delta _ a$, by lemma 20.3.20. Choose $a_ j\ne 0$ tending to zero and set $p_ j=p_{a_ j}$, $p=p_0$. On the complement of any fixed disk about zero the convergence is uniform, including near infinity. Small disks about zero lie in sublevel sets $\{ p_0<-t\} $ with $t$ large, so their capacities tend to zero as the radius tends to zero, by (5.29.4). Therefore $p_ j\to p$ in capacity. Since $\| \delta _{a_ j}-\delta _0\| _{\mathrm{TV}}=2$, (13.28.5) gives the asserted distance.
$\square$
Return to the general curve $Y$. Write $\mu _ u=D_ u+\sigma _ u$, where $D_ u=\sum _{x\in Y}\nu (u,x)\delta _ x$ is the atomic part and $\sigma _ u$ has no atoms. Set $\tau (u)=\sigma _ u(Y)=A-U(u)-D_ u(Y)$, the diffuse polar mass of $u$, and let $\mathcal A_+(Y,\theta )$ denote the set of analytic ordinary models of positive mass.
Proposition 13.28.11.03E01F83CA7A For every $u\in \mathrm{PSH}(Y,\theta )$,
2C63A2647FAC
13.28.12
\begin{equation} \inf _{a\in \mathcal A_+(Y,\theta )}d_\theta (u,a) =d_\theta (u,P_\theta [u]_{\mathcal I})=\tau (u). \end{equation}
On ordinary models, $p\mapsto P_\theta [p]_{\mathcal I}$ is a $1$-Lipschitz retraction onto the ideal models, and $P_\theta [p]_{\mathcal I}$ is the unique ideal model nearest to $p$. There are $a_ j\in \mathcal A_+(Y,\theta )$ with $d_\theta (u,a_ j)\to 0$ if and only if $P_\theta [u]=P_\theta [u]_{\mathcal I}$.
Proof.
The ideal envelope of $u$ is $q_{D_ u}$, by lemma 20.3.20. For any positive atomic measure $E$ of mass at most $A$, the nonatomic measure $\sigma _ u$ and the signed atomic measure $D_ u-E$ are mutually singular. Thus (13.28.5) gives
57E1FB41A4EB
13.28.13
\begin{equation} d_\theta (u,q_ E)=\tau (u)+\| D_ u-E\| _{\mathrm{TV}}. \end{equation}
Among ideal models, the minimum is attained exactly at $E=D_ u$. Since the analytic models of positive mass are dense among the ideal models (corollary 13.28.7), this gives (13.28.12). Taking the atomic part does not increase total variation, which proves the Lipschitz assertion. Finally, lemma 13.28.1 shows that $P_\theta [u]=p_{\mu _ u}$ equals $q_{D_ u}=p_{D_ u}$ if and only if $\mu _ u=D_ u$, that is, $\tau (u)=0$.
$\square$
Example 13.28.14.730582377A86 There is an ordinary model $p$ on $Y$ with zero mass whose multiplier ideals $\mathcal I(tp)$ are trivial for every $t>0$. It satisfies
\[ P_\theta [p]_{\mathcal I}=0,\qquad \inf _{a\in \mathcal A_+(Y,\theta )}d_\theta (p,a)=A. \]
Proof.
Choose a compact real interval inside a coordinate disk. Construct a binary Cantor set $K$ in it: at level $k$ there are $2^ k$ pairwise disjoint intervals of length $r_ k=\exp (-4^{k+1})$, each containing its two children of level $k+1$, and $K$ is the intersection of the unions over all levels. Let $\sigma $ be the probability measure on $K$ assigning mass $2^{-k}$ to each interval of level $k$. It has no atoms. Put $u(x)=A\int _ YG(x,y)\, \mathrm{d}\sigma (y)$, so that $T_ u=A\sigma $. On the chosen compact coordinate disk, $G(x,y)\leq \log |x-y|^2+C$ for a fixed constant $C$. For $x\in K$, integrating over the interval of level $k$ containing $x$, and using $G\leq 0$ elsewhere, gives
\[ u(x)\leq A2^{-k}(2\log r_ k+C)\longrightarrow -\infty . \]
Thus $u=-\infty $ on $K$, while $u$ is smooth off $K$, since $\mathrm{dd}^{\mathrm{c}}u=-\theta $ there. Hence $K$ is polar, $\mu _ u=A\sigma $ and $U(u)=0$. By lemma 13.28.1, $p=P_\theta [u]$ has the same polar curvature. Since this measure already has mass $A$, we get $T_ p=T_ u$, and therefore $p=u-\sup _ Yu$. The Lelong numbers of $p$ vanish because $\sigma $ has no atoms, so all its multiplier ideals are trivial and its ideal envelope is zero. Finally $\tau (p)=A$, which gives the distance by (13.28.12).
$\square$
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