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10.31.43 General measures with a model reference10C7F976A14C

We now prove the existence statements of theorem 10.31.3. Suppose first that $\mu $ is dominated by the Monge–Ampère measure of a bounded potential. The supersolution corollary gives $Q\in \mathcal E_\varphi $ with a nonzero weighted measure $\mathrm{e}^{-Q}\mu _ Q\leq \mu $. Among the potentials $w\in \mathcal E_\varphi $ whose weighted measure $\mathrm{e}^{-w}\mu _ w$ lies between this measure and $\mu $, we maximize the weighted mass. If a maximizer left part of $\mu $ uncovered, weighted addition of a supersolution for the remainder would increase the weighted mass; hence the maximizer solves the equation. Truncating densities then treats every finite non-pluripolar measure.

Theorem 10.31.44.D5758568A543 Let $\mu $ be a nonzero finite non-pluripolar measure and let $\lambda >0$. There is a unique $u\in \mathcal E_\varphi $ such that

\[ \mathrm{MA}_\theta (u)=\mathrm{e}^{\lambda u}\mu . \]

Proof. We first take $\lambda =1$ and suppose that

\[ \mu \leq A\sigma ,\qquad A>0,\qquad \sigma =\mathrm{MA}_\omega (\psi ),\quad \psi \in \mathrm{PSH}(X,\omega )\cap L^\infty (X). \]

Corollary 10.31.28 gives $Q\in \mathcal E_\varphi $ such that

\[ \nu _0=\mathrm{e}^{-Q}\mu _ Q\leq \mu \]

is a finite nonzero measure. Consider

\[ \mathcal T=\{ w\in \mathcal E_\varphi : \nu _0\leq \mathrm{e}^{-w}\mu _ w\leq \mu \} . \]

The family contains $Q$. For $w\in \mathcal T$, exponential order (corollary 13.19.3) gives $w\leq Q$. Also

\[ \ell \leq \mu _ w(X)\leq \mathrm{e}^{\sup _ Xw}\mu (X), \qquad \sup _ Xw\geq \log \frac{\ell }{\mu (X)}. \]

These bounds prevent the collapse of any sequence in $\mathcal T$.

Let

\[ \alpha =\sup _{w\in \mathcal T}\int _ X\mathrm{e}^{-w}\, \mu _ w\leq \mu (X), \]

and choose $w_ j\in \mathcal T$ whose weighted masses tend to $\alpha $. Extract an $L^1$ limit $w\not\equiv -\infty $. Since

\[ \mu _{w_ j}\leq \mathrm{e}^{\sup _ XQ}\mu , \]

the fixed-dominator theorem theorem 10.31.5 gives $w\in \mathcal E_\varphi $, convergence in capacity, and $\mu _{w_ j}\rightharpoonup \mu _ w$. Put $\nu _ j=\mathrm{e}^{-w_ j}\mu _{w_ j}$. After a further extraction, these finite measures converge weakly to a measure $\nu $, and

\[ \nu _0\leq \nu \leq \mu ,\qquad \nu (X)=\alpha . \]

We claim that $\mu _ w=\mathrm{e}^ w\nu $. By lemma 5.44.2,

\[ \int _ X|\mathrm{e}^{w_ j}-\mathrm{e}^ w|\, \mathrm{d}\mu \longrightarrow 0. \]

Let $f$ be continuous. Since $\nu _ j\leq \mu $, replacing $\mathrm{e}^{w_ j}$ by $\mathrm{e}^ w$ in $\int _ Xf \mathrm{e}^{w_ j}\, \mathrm{d}\nu _ j$ changes the integral by an amount tending to zero. For the remaining integral, approximate the fixed bounded measurable function $f \mathrm{e}^ w$ in $L^1(\mu )$ by continuous functions. Since $\nu _ j,\nu \leq \mu $, the approximation error is uniform in $j$, while the integrals of each continuous approximation converge by weak convergence. Thus

\[ \int _ Xf\, \mu _{w_ j} =\int _ Xf \mathrm{e}^{w_ j}\, \mathrm{d}\nu _ j \longrightarrow \int _ Xf \mathrm{e}^ w\, \mathrm{d}\nu . \]

This proves the claim. The measure $\nu $ does not charge the poles of $w$, so $\mathrm{e}^{-w}\mu _ w=\nu $. Hence $w\in \mathcal T$ attains the maximum $\alpha $.

Suppose that $\mu -\nu $ were nonzero. Then corollary 10.31.28, applied to $\mu -\nu $, would give $v\in \mathcal E_\varphi $ with

\[ 0\ne \nu _ v=\mathrm{e}^{-v}\mu _ v\leq \mu -\nu . \]

In particular $\mu _ v\leq \mathrm{e}^{\sup _ Xv}\mu \leq A \mathrm{e}^{\sup _ Xv}\sigma $, so the bounded-carrier hypothesis of theorem 10.31.38 holds. That theorem, with $\lambda =1$, gives $a\in \mathcal E_\varphi $ with

\[ \mathrm{e}^{-a}\mu _ a=\mathrm{e}^{-w}\mu _ w+\mathrm{e}^{-v}\mu _ v=\nu +\nu _ v. \]

The right-hand side lies between $\nu _0$ and $\mu $, so $a\in \mathcal T$, but its mass exceeds $\alpha $. This contradicts maximality. Therefore $\nu =\mu $, and $w$ solves the equation.

Now let $\mu $ be any nonzero finite non-pluripolar measure. The bounded-carrier decomposition lemma 15.24.4, applied to $\omega $, writes

\[ \mu =f\sigma ,\qquad \sigma =\mathrm{MA}_\omega (\psi ),\quad \psi \in \mathrm{PSH}(X,\omega )\cap L^\infty (X),\quad 0\leq f\in L^1(\sigma ). \]

Set $f_ k=\min (f,k)$ and $\mu _ k=f_ k\sigma $. These measures are nonzero, and the first part gives $u_ k\in \mathcal E_\varphi $ with $\mu _{u_ k}=\mathrm{e}^{u_ k}\mu _ k$. Since $\mu _ k$ increases with $k$, exponential order shows that $u_ k$ decreases. The uniform bound

\[ \sup _ Xu_ k\geq \log \frac{\ell }{\mu (X)} \]

shows that the decreasing limit $u$ is not identically $-\infty $. Moreover $\mu _{u_ k}\leq \mathrm{e}^{\sup _ Xu_1}\mu $, so fixed-dominator continuity gives $u\in \mathcal E_\varphi $ and weak convergence of these measures. On the right-hand side, $\mathrm{e}^{u_ k}f_ k\to \mathrm{e}^ u f$ in $L^1(\sigma )$ by dominated convergence, with dominating function $\mathrm{e}^{\sup _ Xu_1}f$. Thus $\mu _ u=\mathrm{e}^ u\mu $.

For general $\lambda >0$, apply the result for exponent one in the background $\lambda \theta $, with model $\lambda \varphi $ and datum $\lambda ^ n\mu $, and divide the resulting potential by $\lambda $. The scaling of the relative class and of the Monge–Ampère measure gives the equation. Uniqueness follows by applying corollary 13.19.3 to two solutions in both directions. $\square$

Theorem 10.31.45.DDDCE55695E1 For every nonzero finite non-pluripolar measure $\mu $, there are $u\in \mathcal E_\varphi $ and $c>0$ such that

\[ \sup _ Xu=0,\qquad \mathrm{MA}_\theta (u)=c\mu . \]

The scalar $c$ is unique and satisfies

\[ \frac{\ell }{\mu (X)}\leq c\leq \frac{M}{\mu (X)}. \]

Proof. For each integer $j\geq 1$, the preceding theorem gives a solution of

\[ \mu _{u_ j}=\mathrm{e}^{u_ j/j}\mu ,\qquad u_ j\in \mathcal E_\varphi . \]

Put $S=\sup _ Xu_1$ and $w_ j=u_1+(j-1)S$. Then $w_ j/j\geq u_1$, and hence

\[ \mu _{w_ j}=\mathrm{e}^{u_1}\mu \leq \mathrm{e}^{w_ j/j}\mu . \]

Exponential order at exponent $1/j$ gives $u_ j\leq w_ j$. Define

\[ v_ j=u_ j-\sup _ Xu_ j,\qquad c_ j=\mathrm{e}^{(\sup _ Xu_ j)/j}. \]

The upper bound just proved and the positive lower volume $\ell $ imply

\[ \frac{\ell }{\mu (X)}\leq c_ j\leq \mathrm{e}^ S, \qquad \mu _{v_ j}=c_ j \mathrm{e}^{v_ j/j}\mu \leq \mathrm{e}^ S\mu . \]

The envelope identity gives $v_ j\leq \varphi $. Theorem 5.25.2 gives a subsequence $j_ k$ along which $v_{j_ k}\to u$ in $L^1$, where $u\not\equiv -\infty $ and $\sup _ Xu=0$, and $c_{j_ k}\to c>0$. Fixed-dominator continuity gives $u\in \mathcal E_\varphi $ and $\mu _{v_{j_ k}}\rightharpoonup \mu _ u$.

Lemma 5.44.5, which holds for every smooth background, gives $\mathrm{e}^{v_ j/j}\to 1$ in $L^1(\mu )$. Consequently $c_{j_ k}\mathrm{e}^{v_{j_ k}/j_ k}\mu \to c\mu $ in total variation, and the limiting equation is $\mu _ u=c\mu $. Integrating it and using (10.31.1) gives the stated bounds for $c$. The scalar comparison in corollary 13.19.3 gives uniqueness of $c$. $\square$

For $L^ p$ densities, subsection 10.31.52 proves the stronger conclusion $u\sim \varphi $.

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