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Proposition 15.26.28F3C95237950

Proposition 15.26.2.8F3C95237950 The measure $\rho $ is a singular non-pluripolar probability. There are $k>0$ and $u_\rho \in \mathrm{PSH}(X,h)\cap C^{0,1/2}(X)$ with $\sup _ Xu_\rho =0$ such that

\[ h+\mathrm{dd}^{\mathrm{c}}u_\rho \geq h/2,\qquad \mathrm{MA}_ h(u_\rho )\geq k\rho ,\qquad 0<\mathrm{MA}_ h(u_\rho )(X)<\infty . \]

Proof. In the coordinate ball write $R=|z|$ and set

\[ \psi _ j=\chi \log \max \{ R^2,r_ j^2\} +(1-\chi ), \]

extending $\psi _ j$ by one outside it. On the transition region of $\chi $, $R$ is bounded away from zero and exceeds all $r_ j$. Hence all $\psi _ j$ agree there with the same smooth function. Where $\chi =1$ they are plurisubharmonic, and outside its support they are constant. One fixed $K\geq 1$ therefore satisfies $\mathrm{dd}^{\mathrm{c}}\psi _ j\geq -Kh$ for every $j$. Put

\[ Z=2K\sum _{j\geq 1}\sqrt{r_ j},\qquad d_ j=\frac{\sqrt{r_ j}}Z,\qquad u_0=\sum _{j\geq 1}d_ j\psi _ j. \]

The estimate $\| \psi _ j\| _\infty \leq C(1+|\log r_ j|)$ gives uniform convergence, and $\sum d_ j=1/(2K)$ yields $h+\mathrm{dd}^{\mathrm{c}}u_0\geq h/2$.

For two points of the inner ball at Euclidean distance $t$, the reverse triangle inequality gives

\[ |\log \max \{ |z|^2,r_ j^2\} -\log \max \{ |z'|^2,r_ j^2\} | \leq 2\log (1+t/r_ j). \]

The contribution of $r_ j\geq t$ is at most $Ct\sum _{r_ j\geq t}r_ j^{-1/2}\leq C\sqrt t$. For $r_ j<t$, summing the geometric tail gives at most $C\sqrt t\sum _{\ell \geq 0}2^{-\ell /2}(1+\ell )$. On the cutoff transition and outside, the series is a fixed smooth function. These estimates give a local $1/2$-Hölder bound near every point. A finite cover and the bound on the oscillation give the global bound.

On the smaller ball, the currents $\mathrm{dd}^{\mathrm{c}}\psi _ j$ are closed and positive. Expand the product of $h+\sum _{j\leq N}d_ j\mathrm{dd}^{\mathrm{c}}\psi _ j$ there and retain its positive diagonal terms. By lemma 5.27.26, these are $d_ j^ n\sigma _ j$. Uniform convergence of the corrected bounded potentials gives weak convergence of their products. Testing against nonnegative functions and first retaining any fixed finite number of diagonal terms therefore gives

\[ \mathrm{MA}_ h(u_0)\geq \sum _{j\geq 1}d_ j^ n\sigma _ j =\frac{S_ n}{Z^ n}\rho . \]

Here the right-hand side is supported strictly inside the smaller ball, so the inequality extends to $X$. Each $\sigma _ j$ is non-pluripolar by the same lemma; countable additivity gives that property for $\rho $. The countable union of the spheres has zero smooth volume, which proves singularity. Local bounded-product estimates on a finite cover make the mass of $u_0$ finite, and the retained inequality makes it positive. Set $k=S_ n/Z^ n$ and subtract $\sup _ Xu_0$ to obtain $u_\rho $. $\square$

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