Theorem 18.1.46 (Asymptotic Riemann–Roch formula).FEA63C5AE11F Let $(L,h)$ be a Hermitian pseudo-effective line bundle on $X$ and $T$ be a holomorphic line bundle on $X$. We have
A09BDD8C8D10
18.1.47
In particular, the limit exists.
FEA63C5AE11FTheorem 18.1.46 (Asymptotic Riemann–Roch formula).FEA63C5AE11F Let $(L,h)$ be a Hermitian pseudo-effective line bundle on $X$ and $T$ be a holomorphic line bundle on $X$. We have
A09BDD8C8D10
18.1.47
In particular, the limit exists.
Proof of theorem 18.1.46. Step 1. We first handle the case where $\theta _{\varphi }$ is a Kähler current. Fix a Kähler form $\omega \geq \theta $ on $X$ such that $\theta _{\varphi }\geq 2\delta \omega $ for some $\delta \in (0,1)$.
Let $(\varphi _ j)_ j$ be a quasi-equisingular approximation of $\varphi $ in $\mathrm{PSH}(X,\theta )$. We may assume that $\theta _{\varphi _ j}\geq \delta \omega $ for all $j$. From proposition 18.1.48, we know that for each $j\geq 1$,
It follows from theorem 18.1.2 and theorem 16.9.57 that the right-hand side converges to $\operatorname{vol}\theta _{\varphi }$ as $j\to \infty $. Therefore,
Conversely, fix an integer $N>\delta ^{-1}$. From theorem 18.1.2 and theorem 16.9.30, we know that
17BF54CBA55B
18.1.49
Therefore, by 13.13.30, we can find $j_0>0$ such that for $j\geq j_0$, there is $\psi \in \mathrm{PSH}(X,\theta )_{>0}$ (depending on $j$) with
1375552B142A
18.1.50
For each $k>0$, we write $k=k'N-r$, where $k'\in \mathbb {N}$ and $r\in \{ 0,1,\ldots ,N-1\} $. Then we compute for $j\geq j_0$ and large enough $k$ (to be specified shortly) that
where the third line follows from (18.1.50), the fourth line can be argued as follows: For large enough $k$, there is a non-zero section $s\in \mathrm{H}^0(X,L^{k'}\otimes \mathcal{I}(k'\psi ))$ by 13.13.48. It follows from 5.18.15 that for large enough $k$,
It follows that multiplication by $s$ gives an injective map
Next observe that
Since $N>\delta ^{-1}$, this is a Kähler current. Hence proposition 18.1.48 is applicable. We let $k\to \infty $ to conclude that
where $C$ is a constant independent of $N$ and $j$. Letting $j\to \infty $ and then $N\to \infty $ and using (18.1.49), we find that
Therefore, (18.1.47) follows.
Step 2. We handle the case where $\operatorname{vol}\theta _{\varphi }>0$. We may assume that $\varphi $ is $\mathcal{I}$-model.
First observe that $L$ is big by proposition 13.13.3. Hence $X$ is projective. Take a very ample line bundle $A$ on $X$ and a Kähler form $\omega $ in $c_1(A)$. Take a Hermitian metric $h_ A$ on $A$ with $\mathrm{dd}^{\mathrm{c}}h_ A=\omega $.
Fix $N\in \mathbb {Z}_{>0}$. We decompose any $k>0$ as $k=k'N+r$ with $k'\in \mathbb {N}$ and $r\in \{ 0,1,\ldots ,N-1\} $. Then
Therefore,
where the third line uses multiplication by a non-zero section of $A^{k'}$, and we have applied Step 1 to the Hermitian pseudo-effective line bundle $(L^ N\otimes A,h^{\otimes N}\otimes h_ A)$ on the fourth line. On the other hand, since $\varphi $ is $\mathcal{I}$-good by example 18.1.11, 18.1.8 gives
It follows from proposition 16.3.10 that
Letting $N\to \infty $, we conclude
It remains to argue the reverse inequality.
Choose $\psi \in \mathrm{PSH}(X,\theta )$ such that $\theta _{\psi }$ is a Kähler current and $\psi \leq \varphi $. The existence of $\psi $ is guaranteed by 13.13.47. Then for any $t\in (0,1)$, we set
It follows again from Step 1 that
On the other hand, by theorem 18.1.32 and corollary 16.9.38,
So we find
We conclude (18.1.47) in this case.
Step 3. We finally handle the case where $\operatorname{vol}\theta _{\varphi }=0$. Replacing $\varphi $ by $P_{\theta }[\varphi ]_{\mathcal{I}}$, we may assume that $\varphi $ is $\mathcal{I}$-model.
Assume that (18.1.47) fails. That is,
then $L$ is a big line bundle and hence $X$ is projective.
Fix a very ample line bundle $A$ on $X$ and a Kähler form $\omega \in c_1(A)$. Take a decreasing sequence $(\epsilon _ j)_ j$ of rational numbers with limit $0$ and a quasi-equisingular approximation $(\varphi _ j)_ j$ of $\varphi $ with $\varphi _ j\in \mathrm{PSH}(X,\theta +\epsilon _ j\omega )_{>0}$.
We claim that as $j\to \infty $, the sequence $P_{\theta +\epsilon _ j\omega }[\varphi _ j]$ is decreasing with limit $\varphi $.
It is clear that this sequence is decreasing. Let $\psi $ denote its limit for the moment. It is also clear that $\psi \geq \varphi $. Since $\varphi $ is $\mathcal{I}$-model, it remains to show that $\psi \preceq _{\mathcal{I}}\varphi $. Fix $\lambda >0$. By strong openness, choose $\lambda '>\lambda $ such that $\mathcal{I}(\lambda \psi )=\mathcal{I}(\lambda '\psi )$. For $j$ large enough, the quasi-equisingularity of $(\varphi _ j)_ j$ gives
where the first inclusion uses $\psi \leq P_{\theta +\epsilon _ j\omega }[\varphi _ j]$ and $P_{\theta +\epsilon _ j\omega }[\varphi _ j]\sim _{\mathcal{I}}\varphi _ j$. Thus $\psi \preceq _{\mathcal{I}}\varphi $, and the claim follows.
By our claim, proposition 16.3.10 and proposition 16.4.4, we find that
56B91126C3D7
18.1.51
Fix $j>0$, take an integer $N>0$ so that $N\epsilon _ j$ is an integer. Then we compute
where the third line follows by writing $k=Nk'+a$ as before, we applied Step 2 on the last line. Dividing by $N^ n$, we find that
Since we know (18.1.51), letting $j\to \infty $, we conclude that
which is a contradiction. Hence (18.1.47) is established in full generality. $\square$
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