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Theorem 18.1.46 (Asymptotic Riemann–Roch formula)FEA63C5AE11F

Theorem 18.1.46 (Asymptotic Riemann–Roch formula).FEA63C5AE11F Let $(L,h)$ be a Hermitian pseudo-effective line bundle on $X$ and $T$ be a holomorphic line bundle on $X$. We have

A09BDD8C8D10 18.1.47
\begin{equation} \lim _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(h^ k)\right)=\operatorname{vol}\left(\mathrm{dd}^{\mathrm{c}}h\right). \end{equation}

In particular, the limit exists.

Proof of theorem 18.1.46. Step 1. We first handle the case where $\theta _{\varphi }$ is a Kähler current. Fix a Kähler form $\omega \geq \theta $ on $X$ such that $\theta _{\varphi }\geq 2\delta \omega $ for some $\delta \in (0,1)$.

Let $(\varphi _ j)_ j$ be a quasi-equisingular approximation of $\varphi $ in $\mathrm{PSH}(X,\theta )$. We may assume that $\theta _{\varphi _ j}\geq \delta \omega $ for all $j$. From proposition 18.1.48, we know that for each $j\geq 1$,

\[ \varlimsup _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\leq \lim _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi _ j)\right)=\operatorname{vol}\theta _{\varphi _ j}. \]

It follows from theorem 18.1.2 and theorem 16.9.57 that the right-hand side converges to $\operatorname{vol}\theta _{\varphi }$ as $j\to \infty $. Therefore,

\[ \varlimsup _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\leq \operatorname{vol}\theta _{\varphi }. \]

Conversely, fix an integer $N>\delta ^{-1}$. From theorem 18.1.2 and theorem 16.9.30, we know that

17BF54CBA55B 18.1.49
\begin{equation} \lim _{j\to \infty }\int _ X \theta _{\varphi _ j}^ n=\int _ X \theta _{P_{\theta }[\varphi ]_{\mathcal{I}}}^ n>0. \end{equation}

Therefore, by 13.13.30, we can find $j_0>0$ such that for $j\geq j_0$, there is $\psi \in \mathrm{PSH}(X,\theta )_{>0}$ (depending on $j$) with

1375552B142A 18.1.50
\begin{equation} (1-N^{-1})\varphi _ j+N^{-1}\psi \leq P_{\theta }[\varphi ]_{\mathcal{I}}. \end{equation}

For each $k>0$, we write $k=k'N-r$, where $k'\in \mathbb {N}$ and $r\in \{ 0,1,\ldots ,N-1\} $. Then we compute for $j\geq j_0$ and large enough $k$ (to be specified shortly) that

\[ \begin{aligned} & h^0\left(X,T\otimes L^{k}\otimes \mathcal{I}(k\varphi )\right)\\ \geq & h^0\left(X,T\otimes L^{-r}\otimes L^{k'N}\otimes \mathcal{I}(k'N\varphi )\right)\\ \geq & h^0\left(X,T\otimes L^{-r}\otimes L^{k'N}\otimes \mathcal{I}\left(k'(\psi +(N-1)\varphi _ j)\right)\right)\\ \geq & h^0\left(X,T\otimes L^{-r}\otimes L^{k'(N-1)}\otimes \mathcal{I}\left(k'N\varphi _ j\right)\right), \end{aligned} \]

where the third line follows from (18.1.50), the fourth line can be argued as follows: For large enough $k$, there is a non-zero section $s\in \mathrm{H}^0(X,L^{k'}\otimes \mathcal{I}(k'\psi ))$ by 13.13.48. It follows from 5.18.15 that for large enough $k$,

\[ \mathcal{I}\left(k'N\varphi _ j\right)\subseteq \mathcal{I}_{\infty }\left(k'(N-1)\varphi _ j\right). \]

It follows that multiplication by $s$ gives an injective map

\[ \begin{split} \mathrm{H}^0\left(X,T\otimes L^{-r}\otimes L^{k'(N-1)}\otimes \mathcal{I}\left(k'N\varphi _ j\right)\right)\hookrightarrow \\ \mathrm{H}^0\left(X,T\otimes L^{-r}\otimes L^{k'N}\otimes \mathcal{I}\left(k'\psi +k'(N-1)\varphi _ j\right)\right). \end{split} \]

Next observe that

\[ (N-1)\theta +N\mathrm{dd}^{\mathrm{c}}\varphi _ j= N\theta _{\varphi _ j}-\theta \geq N\delta \omega -\theta \geq (N\delta -1)\omega . \]

Since $N>\delta ^{-1}$, this is a Kähler current. Hence proposition 18.1.48 is applicable. We let $k\to \infty $ to conclude that

\[ \begin{aligned} \varliminf _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^{k}\otimes \mathcal{I}(k\varphi )\right) \geq & N^{-n}\int _{X} \left( (N-1)\theta +N\mathrm{dd}^{\mathrm{c}}\varphi _ j\right)^ n\\ =& \int _ X \left((1-N^{-1})\theta +\mathrm{dd}^{\mathrm{c}}\varphi _ j \right)^ n\\ \geq & \int _ X \left(\theta +\mathrm{dd}^{\mathrm{c}}\varphi _ j \right)^ n -C N^{-1}, \end{aligned} \]

where $C$ is a constant independent of $N$ and $j$. Letting $j\to \infty $ and then $N\to \infty $ and using (18.1.49), we find that

\[ \varliminf _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^{k}\otimes \mathcal{I}(k\varphi )\right)\geq \int _ X \theta _{P_{\theta }[\varphi ]_{\mathcal{I}}}^ n. \]

Therefore, (18.1.47) follows.

Step 2. We handle the case where $\operatorname{vol}\theta _{\varphi }>0$. We may assume that $\varphi $ is $\mathcal{I}$-model.

First observe that $L$ is big by proposition 13.13.3. Hence $X$ is projective. Take a very ample line bundle $A$ on $X$ and a Kähler form $\omega $ in $c_1(A)$. Take a Hermitian metric $h_ A$ on $A$ with $\mathrm{dd}^{\mathrm{c}}h_ A=\omega $.

Fix $N\in \mathbb {Z}_{>0}$. We decompose any $k>0$ as $k=k'N+r$ with $k'\in \mathbb {N}$ and $r\in \{ 0,1,\ldots ,N-1\} $. Then

\[ h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\leq h^0\left(X,T\otimes L^ r \otimes L^{k'N}\otimes \mathcal{I}(k'N\varphi )\right). \]

Therefore,

\[ \begin{aligned} & \varlimsup _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\\ \leq & \max _{r=0,\ldots ,N-1}\varlimsup _{k'\to \infty }\frac{n!}{k'^ nN^ n} h^0\left(X,T\otimes L^ r \otimes L^{k'N}\otimes \mathcal{I}(k'N\varphi )\right)\\ \leq & \max _{r=0,\ldots ,N-1}\varlimsup _{k'\to \infty }\frac{n!}{k'^ nN^ n} h^0\left(X,T\otimes L^ r \otimes L^{k'N}\otimes A^{k'}\otimes \mathcal{I}(k'N\varphi )\right)\\ =& \int _ X \left(N^{-1}\omega +\theta +\mathrm{dd}^{\mathrm{c}}P_{\theta +N^{-1}\omega }[\varphi ]_{\mathcal{I}}\right)^{n}, \end{aligned} \]

where the third line uses multiplication by a non-zero section of $A^{k'}$, and we have applied Step 1 to the Hermitian pseudo-effective line bundle $(L^ N\otimes A,h^{\otimes N}\otimes h_ A)$ on the fourth line. On the other hand, since $\varphi $ is $\mathcal{I}$-good by example 18.1.11, 18.1.8 gives

\[ P_{\theta +N^{-1}\omega }[\varphi ]_{\mathcal{I}}=P_{\theta +N^{-1}\omega }[\varphi ]. \]

It follows from proposition 16.3.10 that

\[ \varlimsup _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\leq \int _ X \left(N^{-1}\omega +\theta +\mathrm{dd}^{\mathrm{c}}\varphi \right)^ n. \]

Letting $N\to \infty $, we conclude

\[ \varlimsup _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\leq \int _ X \theta _{\varphi }^ n. \]

It remains to argue the reverse inequality.

Choose $\psi \in \mathrm{PSH}(X,\theta )$ such that $\theta _{\psi }$ is a Kähler current and $\psi \leq \varphi $. The existence of $\psi $ is guaranteed by 13.13.47. Then for any $t\in (0,1)$, we set

\[ \varphi _ t=(1-t)\varphi +t\psi . \]

It follows again from Step 1 that

\[ \varliminf _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\geq \lim _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi _ t)\right)=\operatorname{vol}\theta _{\varphi _ t}. \]

On the other hand, by theorem 18.1.32 and corollary 16.9.38,

\[ \lim _{t\to 0+}\operatorname{vol}\theta _{\varphi _ t}=\operatorname{vol}\theta _{\varphi }. \]

So we find

\[ \varliminf _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\geq \operatorname{vol}\theta _{\varphi }. \]

We conclude (18.1.47) in this case.

Step 3. We finally handle the case where $\operatorname{vol}\theta _{\varphi }=0$. Replacing $\varphi $ by $P_{\theta }[\varphi ]_{\mathcal{I}}$, we may assume that $\varphi $ is $\mathcal{I}$-model.

Assume that (18.1.47) fails. That is,

\[ \varlimsup _{k\to \infty }\frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\right)\geq \varlimsup _{k\to \infty } \frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)>0, \]

then $L$ is a big line bundle and hence $X$ is projective.

Fix a very ample line bundle $A$ on $X$ and a Kähler form $\omega \in c_1(A)$. Take a decreasing sequence $(\epsilon _ j)_ j$ of rational numbers with limit $0$ and a quasi-equisingular approximation $(\varphi _ j)_ j$ of $\varphi $ with $\varphi _ j\in \mathrm{PSH}(X,\theta +\epsilon _ j\omega )_{>0}$.

We claim that as $j\to \infty $, the sequence $P_{\theta +\epsilon _ j\omega }[\varphi _ j]$ is decreasing with limit $\varphi $.

It is clear that this sequence is decreasing. Let $\psi $ denote its limit for the moment. It is also clear that $\psi \geq \varphi $. Since $\varphi $ is $\mathcal{I}$-model, it remains to show that $\psi \preceq _{\mathcal{I}}\varphi $. Fix $\lambda >0$. By strong openness, choose $\lambda '>\lambda $ such that $\mathcal{I}(\lambda \psi )=\mathcal{I}(\lambda '\psi )$. For $j$ large enough, the quasi-equisingularity of $(\varphi _ j)_ j$ gives

\[ \mathcal{I}(\lambda '\psi )\subseteq \mathcal{I}(\lambda '\varphi _ j)\subseteq \mathcal{I}(\lambda \varphi ), \]

where the first inclusion uses $\psi \leq P_{\theta +\epsilon _ j\omega }[\varphi _ j]$ and $P_{\theta +\epsilon _ j\omega }[\varphi _ j]\sim _{\mathcal{I}}\varphi _ j$. Thus $\psi \preceq _{\mathcal{I}}\varphi $, and the claim follows.

By our claim, proposition 16.3.10 and proposition 16.4.4, we find that

56B91126C3D7 18.1.51
\begin{equation} \lim _{j\to \infty } \int _ X \left(\theta +\epsilon _ j\omega +\mathrm{dd}^{\mathrm{c}}\varphi _ j\right)^ n=\int _ X \theta _{\varphi }^ n=0. \end{equation}

Fix $j>0$, take an integer $N>0$ so that $N\epsilon _ j$ is an integer. Then we compute

\[ \begin{aligned} & \varlimsup _{k\to \infty } \frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\\ \leq & \varlimsup _{k\to \infty } \frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi _ j)\right)\\ \leq & \max _{a=0,\ldots ,N-1}\varlimsup _{k'\to \infty } \frac{n!}{(k'N)^ n}h^0\left(X,T\otimes L^ a\otimes L^{Nk'}\otimes \mathcal{I}(Nk'\varphi _ j)\right)\\ \leq & \max _{a=0,\ldots ,N-1}\varlimsup _{k'\to \infty } \frac{n!}{(k'N)^ n}h^0\left(X,T\otimes L^ a\otimes L^{Nk'}\otimes A^{k'N\epsilon _ j}\otimes \mathcal{I}(Nk'\varphi _ j)\right)\\ =& \frac{1}{N^ n}\int _ X \left( N\theta +\epsilon _ jN\omega +N\mathrm{dd}^{\mathrm{c}}\varphi _ j \right)^ n, \end{aligned} \]

where the third line follows by writing $k=Nk'+a$ as before, we applied Step 2 on the last line. Dividing by $N^ n$, we find that

\[ \varlimsup _{k\to \infty } \frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)\leq \int _ X \left(\theta +\epsilon _ j\omega +\mathrm{dd}^{\mathrm{c}}\varphi _ j\right)^ n. \]

Since we know (18.1.51), letting $j\to \infty $, we conclude that

\[ \varlimsup _{k\to \infty } \frac{n!}{k^ n}h^0\left(X,T\otimes L^ k\otimes \mathcal{I}(k\varphi )\right)=0, \]

which is a contradiction. Hence (18.1.47) is established in full generality. $\square$

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