Proposition 12.19.18.94417AD14985 On the threefold $X$ of theorem 12.19.1, the Hermitian form $\omega =\alpha +\beta +D$ satisfies
\[ \mathrm{d}(\omega ^2)=0,\qquad \mathrm{dd}^{\mathrm{c}}\omega =2\alpha \wedge \beta \geq 0, \qquad \int _ X\omega ^3=24\pi . \]
For every smooth real function $u$,
9E38044EBFA0
12.19.19
\begin{equation} \int _ X(\omega +\mathrm{dd}^{\mathrm{c}}u)^3 =24\pi -6\int _ X\mathrm{d}u\wedge \mathrm d^{\mathrm c}u\wedge \alpha \wedge \beta . \end{equation}
Consequently $v_+(\omega )=24\pi $. In particular, $X$ has the bounded mass property, while $v_-(h)=0$ for every Hermitian form $h$ on $X$.
Proof.
Although $t$ is defined only on the covering space $\Omega $, both $\mathrm{d}t$ and $\mathrm d^{\mathrm c}t$ descend to $X$. The Fubini–Study potentials $\log \| z\| ^2$ and $\log \| w\| ^2$ give $\mathrm{dd}^{\mathrm{c}}t=\beta -\alpha $. The forms $\alpha ,\beta $ are closed, and $\alpha ^2=\beta ^2=0$ since each is pulled back from a curve. As $D^2=0$, we obtain
\[ \mathrm{d}D=-\mathrm{d}t\wedge (\beta -\alpha ),\qquad \mathrm{dd}^{\mathrm{c}}D=-(\beta -\alpha )^2=2\alpha \wedge \beta , \]
\[ \mathrm{d}(\omega ^2) =-2(\alpha +\beta +D)\wedge \mathrm{d}t\wedge (\beta -\alpha )=0. \]
In the last identity, the term involving $D$ contains $\mathrm{d}t$ twice, and $(\alpha +\beta )\wedge (\beta -\alpha )=0$. Thus $\omega $ is balanced, hence Gauduchon, and the formula for $\mathrm{dd}^{\mathrm{c}}\omega $ follows from that for $\mathrm{dd}^{\mathrm{c}}D$.
On a fiber, write $\zeta =a+\mathrm{i}b$, where both real periods are $2\pi $. There $t=2a$ plus a constant, so
\[ D|_ E=\frac1\pi \, \mathrm{d}a\wedge \mathrm{d}b, \qquad \int _ ED=4\pi . \]
Since $\omega ^3=6\alpha \wedge \beta \wedge D$, fiber integration and the normalization of the Fubini–Study forms give $\int _ X\omega ^3=24\pi $.
The identity (12.16.4) for Gauduchon metrics on threefolds, with $\mathrm{dd}^{\mathrm{c}}\omega =2\alpha \wedge \beta $, gives (12.19.19). Its last integral is nonnegative. Thus every smooth strictly $\omega $-plurisubharmonic potential has mass at most $24\pi $, and the constant potential attains this value. Regularization of bounded potentials, as in the proof of theorem 12.15.4, gives the same supremum over bounded potentials, so $v_+(\omega )=24\pi $. The metric independence in proposition 13.14.15 then gives the bounded mass property of $X$. The assertion about the lower mass is theorem 12.19.1.
$\square$
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